How to make Serial.read() return an integer instead of an ascii value?

Question

I want Serial.read() to return an integer instead of an ASCII value. For example, in the below code if I input 2, I want the output as 2 instead of 50

void setup(){
 Serial.begin();
}
void loop(){
 if(Serial.available()){
 int t = Serial.read();
 Serial.println(t);
}

• jsotola: your code does not compile because of a syntax error
• jsotola: Serial.read() returns a byte ... what that byte means to you, is not realted to that fact

Answer 1

If it's a single digit:

if (t >= '0' && t <= '9') {
 int numeric_value = t - '0';
} else {
 // Handle the input error.
}

Answer 2

You can use an alternate method like this

void setup()
{
Serial.begin(9600);
}
void loop()
{
 if(Serial.available()){
 String a = Serial.read();
 int b = a.toInt();
 Serial.println(b);
}