C++ trim char array

Question

I have a char array of length 10. It gets filled with an unpredictable number of chars, usually up to 6.

char charDummy[10] = "";

When i concatenate the char array with another, I get spaces, which are unwanted in later parsing.

char postStr[300] = "";
strcat(postStr, "&field1=");
strcat(postStr,dtostrf(rain05m,6,2,charDummy));

How do I trim a char array directly?

Workaround: loop thru the array and copy valid characters to a new char array with perfect number of rows. Due to memory constraints, I need to be parcimonious with the amount of variables created.

Answer 1

Your problem is that dtostrf() right-aligns the value in the space allotted to it. The simple answer is to tell it to left-align instead:

Conversion is done in the format "[-]d.ddd". The minimum field width of the output string (including the possible '.' and the possible sign for negative values) is given in width, and prec determines the number of digits after the decimal sign. width is signed value, negative for left adjustment.

AVR LIBC Manual

So, just make your width negative and it will left align.

• AnT stands with Russia: @tony gil: The string terminator (ASCII 0) has nothing to do with NULL and is never referred to as NULL. NULL is a completely different, unrelated thing in C and C++.