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I have to input 5 words and organize. In order to organize words, I have to get them into Array of String to compare. I succeed to get char[buffer] into String in_str but somehow in_str doesn't get into str[5]. is String str[i]=in_str; Wrong?? How can I put in_str to Array of String str??

void setup() {
 Serial.begin(9600); }
void loop() {
 int state = 1, len = 0 ,i=0, k=1;
 char buffer[128];
 String str[5];
 while (true) {
 if (state == 1) {
 Serial.print("Enter the ");
 Serial.print(k);
 Serial.print("th Word --> ");
 state = 2;
 } 
 while (Serial.available()) { 
 char data = Serial.read();
 if (data == '\n') { 
 buffer[len] = '0円';
 String in_str = buffer;
 String str[i]=in_str;
 Serial.println(in_str); 
 i=i+1;
 k=k+1;
 len = 0;
 if(i>4){state = 3; }
 else {state = 1;} 
 break;
 }
 buffer[len++] = data;
 }
 if(state==3){
 Serial.println("After Sorting");
 for (int i = 0; i < 4; i++) {
 for (int j = i + 1; j < 5; j++) {
 int compare = str[i].compareTo(str[j]);
 if (compare > 0) { String temp = str[i];
 str[i] = str[j];
 str[j] = temp;
 }
 }
 }
 for (int i = 0; i < 5; i++) {
 Serial.println(String(i) + " : " + str[i]);
 }
 break; 
 }
 }
}
jose can u c
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asked Mar 29, 2018 at 14:28

1 Answer 1

1

When you write String str[i]=in_str; that is wrong. You only write the type when you are declaring the variable, once.

When assigning, you need only write the variable name, not the type: str[i]=in_str;

answered Mar 29, 2018 at 14:34
1
  • I thought like hours to solve this problem but this was a simple mistake.. thanks for your help Commented Mar 29, 2018 at 14:41

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