0

I am integrating thingspeak and arduino plus Esp8266 mean making a simple project which contain my android app to update the thingspeak channel and then want to read the data of that channel via arduino uno. the android parts works fine but at the arduino side i got stuck and unable to read the channel data via esp8266(attached to my arduino uno). Here is my code.any help would be appreciated. it shows in serial monitor connecting to thingspeak.com and show nothing next.

#include "WiFiEsp.h"
// Emulate Serial1 on pins 6/7 if not present
#ifndef HAVE_HWSERIAL1
#include "SoftwareSerial.h"
SoftwareSerial Serial1(2,3); // RX, TX
#endif
char ssid[] = "M T G"; // your network SSID (name)
char pass[] = "androidGUII"; // your network password
int status = WL_IDLE_STATUS; // the Wifi radio's status
char server[] = "arduino.cc";
// Initialize the Ethernet client object
WiFiEspClient client;
static const char* host = "api.thingspeak.com";
static const char* apiKey = "xxxxxxxxxxxxxxxxxxxxxxxxxx";
void setup()
{
 // initialize serial for debugging
 Serial.begin(115200);
 // initialize serial for ESP module
 Serial1.begin(9600);
 // initialize ESP module
 WiFi.init(&Serial1);
 // check for the presence of the shield
 if (WiFi.status() == WL_NO_SHIELD) {
 Serial.println("WiFi shield not present");
 // don't continue
 while (true);
 }
 // attempt to connect to WiFi network
 while ( status != WL_CONNECTED) {
 Serial.print("Attempting to connect to WPA SSID: ");
 Serial.println(ssid);
 // Connect to WPA/WPA2 network
 status = WiFi.begin(ssid, pass);
 }
 // you're connected now, so print out the data
 Serial.println("You're connected to the network");
 printWifiStatus();
 Serial.println();
}
void loop()
{
 const int httpPort = 80;
 if (!client.connect(host, httpPort)) {
 Serial.println("connection failed");
 return;
 }
 client.println("GET /channels/xxxxxxx/feeds.json?api_key=xxxxxxxxxx&results=2 HTTP/1.1");
 while (client.available() == 0); // wait till something comes in; you may want to add a timeout here
 Serial.println(client.read());
 client.stop(); // close socket
 delay(10000);
}
void printWifiStatus()
{
 // print the SSID of the network you're attached to
 Serial.print("SSID: ");
 Serial.println(WiFi.SSID());
 // print your WiFi shield's IP address
 IPAddress ip = WiFi.localIP();
 Serial.print("IP Address: ");
 Serial.println(ip);
 // print the received signal strength
 long rssi = WiFi.RSSI();
 Serial.print("Signal strength (RSSI):");
 Serial.print(rssi);
 Serial.println(" dBm");
}
asked Mar 16, 2018 at 19:03
3
  • 1
    forum.arduino.cc/index.php?topic=535651 Commented Mar 16, 2018 at 19:14
  • dear this is my question which is not answered yet there too..thats' why i posted it here.thank for your time Commented Mar 16, 2018 at 19:16
  • @mtg client.read() reads a single byte. I doubt that's what you want. Commented Mar 16, 2018 at 19:40

1 Answer 1

1

HTTP GET request needs to end with an empty line and HTTP 1.1 requires a Host header.

Add an empty line and eiher change the HTTP version to 1.0

client.print("GET /channels/421932/feeds.json?api_key=");
client.print(apiKey);
client.println("&results=2 HTTP/1.0");
client.println(); // empty line

or add the Host header

client.print("GET /channels/421932/feeds.json?api_key=");
client.print(apiKey);
client.println("&results=2 HTTP/1.1");
client.print("Host:");
client.println(host);
client.println(); // empty line
answered Mar 16, 2018 at 19:25
5
  • the empty line is only for requests with body like POST request, to mark the start of the request body Commented Mar 16, 2018 at 19:28
  • @Juraj I tested it in Python by sending it over TCP with only a single pair of "\r\n" and the server didn't respond. Had to be "\r\n\r\n". Commented Mar 16, 2018 at 19:31
  • I looked up the protocol. It requires the empty line after the header for all requests Commented Mar 16, 2018 at 19:43
  • WiFiEsp] Connecting to api.thingspeak.com 13 [WiFiEsp] Disconnecting 3 //now it shows this in serial monitor Commented Mar 17, 2018 at 6:26
  • use the library github.com/mathworks/thingspeak-arduino Commented Mar 17, 2018 at 15:04

Your Answer

Draft saved
Draft discarded

Sign up or log in

Sign up using Google
Sign up using Email and Password

Post as a guest

Required, but never shown

Post as a guest

Required, but never shown

By clicking "Post Your Answer", you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.