1

I am trying to understand in details the (great tutorial and) code of Nick Gammon ''Improved sketch using Timer 1'', available here: http://www.gammon.com.au/forum/?id=12075 . I post the whole code at the end of this in the case the web page would go down.

I find the code quite clear: Nick wants to estimate the value of a capacitor by measuring its characteristic discharge time. For this he uses one of the Arduino timers, together with an interrupt raised by the analog comparator. As the Arduino timer he uses is only 16 bits and he uses a pre-factor of 1 at 16MHz, he expects overflow of the timer to occur so he keeps track of the number of overflows that happened:

ISR (TIMER1_OVF_vect)
{
 ++overflowCount; // count number of Counter1 overflows 
} // end of TIMER1_OVF_vect

However, what I do not understand is why he tries to find a 'missed overflow' in the ISR raised by the analog comparator (this is in the ISR (ANALOG_COMP_vect) function body):

// if just missed an overflow
 if ((TIFR1 & bit (TOV1)) && timer1CounterValue < 256)
 overflowCopy++;

So my questions are:

  • How could a missed overflow happen? 'Naively' I would guess that, as soon as the analog comparator ISR is called, the timer stops incrementing so that it should not overflow after the comparator ISR fires, am I wrong?

  • If there is a timer overflow happening, I understand why one wants to check TIFR1 at TOV1 (this is the overflow flag, set automatically at timer overflow, which should be cleared as a side-effect of execution of ISR(TIMER1_0VF_vect) according to datasheet), why add also the && timer1CounterValue < 256 in the if condition? I understand that 256 is a 'small' value, any reason for this exact numerical value?

Copy of the whole code:

/*
Capacitance meter
Author: Nick Gammon
Date: 27 June 2013
Pulse pin (D2): Connect to capacitor via 10K resistor.
Reference voltage of 0.632 of output pin (pulsePin) connected to D7.
In my case I used 3.06V because I measured 4.84 on the 5V pin.
Measure pin (D6) connected to first leg of capacitor, other leg connected to Gnd.
Like this:
Capacitor to test:
D2 ----> 10K ----> D6 ----> capacitor_under_test ----> Gnd
Reference voltage:
+5V ----> 1.8K ---> D7 ---> 3.1K ----> Gnd
*/
const byte pulsePin = 2;
const float resistance = 10000.0;
volatile boolean triggered;
volatile boolean active;
volatile unsigned long timerCounts;
volatile unsigned long overflowCount;
ISR (TIMER1_OVF_vect)
{
 ++overflowCount; // count number of Counter1 overflows 
} // end of TIMER1_OVF_vect
ISR (ANALOG_COMP_vect)
 {
 // grab counter value before it changes any more
 unsigned int timer1CounterValue;
 timer1CounterValue = TCNT1; // see datasheet, page 117 (accessing 16-bit registers)
 unsigned long overflowCopy = overflowCount;
 if (active)
 {
 // if just missed an overflow
 if ((TIFR1 & bit (TOV1)) && timer1CounterValue < 256)
 overflowCopy++;
 // calculate total count
 timerCounts = (overflowCopy << 16) + timer1CounterValue; // each overflow is 65536 more
 triggered = true;
 digitalWrite (pulsePin, LOW); // start discharging capacitor
 }
 } // end of ANALOG_COMP_vect
void setup ()
 {
 pinMode (pulsePin, OUTPUT);
 digitalWrite (pulsePin, LOW);
 Serial.begin (115200);
 Serial.println ("Started.");
 ADCSRB = 0; // (Disable) ACME: Analog Comparator Multiplexer Enable
 ACSR = bit (ACI) // (Clear) Analog Comparator Interrupt Flag
 | bit (ACIE) // Analog Comparator Interrupt Enable
 | bit (ACIS0) | bit (ACIS1); // ACIS1, ACIS0: Analog Comparator Interrupt Mode Select (trigger on rising edge)
 } // end of setup
void startTiming ()
 {
 active = true;
 triggered = false;
 // prepare timer
 overflowCount = 0; // no overflows yet
 // reset Timer 1
 TCCR1A = 0; 
 TCCR1B = 0; 
 TCNT1 = 0; // Counter to zero
 TIFR1 = bit (TOV1); // clear overflow bit
 // Timer 1 - counts clock pulses
 TIMSK1 = bit (TOIE1); // interrupt on Timer 1 overflow
 // get on with it
 digitalWrite (pulsePin, HIGH); // start charging capacitor
 // start Timer 1, no prescaler
 TCCR1B = bit (CS10);
 } // end of startTiming
void finishTiming ()
 {
 active = false;
 Serial.print ("Capacitance = ");
 float capacitance = (float) timerCounts * 1000.0 / 16.0 / resistance;
 Serial.print (capacitance);
 Serial.println (" nF");
 triggered = false;
 delay (3000);
 } // end of finishTiming
void loop ()
 {
 // start another test?
 if (!active)
 startTiming ();
 // if the ISR noted the time interval is up, display results
 if (active && triggered)
 finishTiming ();
 } // end of loop
asked Dec 11, 2017 at 13:55

1 Answer 1

2

'Naively' I would guess that, as soon as the analog comparator ISR is called, the timer stops incrementing

It doesn't. The timer stops only when you ask it to stop.

Now, consider this scenario:

  • overflowCount = 0, TCNT1 = 0xfffc
  • the ANALOG_COMP interrupt fires, which automatically disables servicing nested interrupts
  • while ISR(ANALOG_COMP_vect) is executing its prologue (saving the execution context), Timer 1 overflows, which sets the TOV1 flag, but the corresponding interrupt is for now pending
  • when timer1CounterValue = TCNT1; gets executed, TCNT1 is now 0x0008.

At this point, we have overflowCount = 0 and timer1CounterValue = 0x0008. If we have no provision for detecting the overflow, we will grossly underestimate the time. This can be fixed by accounting for the missed overflow as

// if just missed an overflow
if (TIFR1 & bit(TOV1))
 overflowCopy++;

The is still an issue however. Think of what would happen if the timer overflows after executing timer1CounterValue = TCNT1; but before reading the TOV1 flag. Then we would unduly increment overflowCopy. This is why the code tests for (TIFR1 & bit(TOV1)) && timer1CounterValue < 256. There is no reason for choosing this particular small value, other than the test being easier to perform in assembly. The compiler is probably smart enough to notice it doesn't need to do a subtraction for this particular value.

answered Dec 11, 2017 at 14:26
4
  • Great, thank you! I had always thought that timers were not working in interrupts and that this is why you cannot use delay() there, am I wrong? Commented Dec 11, 2017 at 14:29
  • Sorry, now I may understand: actually, the problem is not that timers were stopped in interrupts, but that delay() relies on an interrupt itself; is this right? Commented Dec 11, 2017 at 14:31
  • Mmh, no, this is not it: delay does not seem to have rely on any interrupt: void delay(unsigned long ms) { uint32_t start = micros(); while (ms > 0) { yield(); while ( ms > 0 && (micros() - start) >= 1000) { ms--; start += 1000; } } } Commented Dec 11, 2017 at 14:34
  • @Zorglub29: delay() relies on micros() which relies on timer0_overflow_count which is updated by the TIMER0_OVF interrupt. Commented Dec 11, 2017 at 16:39

Your Answer

Draft saved
Draft discarded

Sign up or log in

Sign up using Google
Sign up using Email and Password

Post as a guest

Required, but never shown

Post as a guest

Required, but never shown

By clicking "Post Your Answer", you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.