Servos and Random Number

Question

I am new to coding and this website so I apologize if I make any mistakes. I am trying to get servos to move when a random number is generated. Like if I roll a 2 I want servos 1, 2 and 3 to open and then if I roll a 3 after I want servos 4, 5 and 6 to open. I am able to hold the previous values in the code now but can't get the servos to go with it. Any help is great! Thanks!

#include <Servo.h>
Servo myservo;
int pos = 0; // variable to store the servo position
int x = 0;
int button = 8;
int BUTTON;
int randomNumber;
int xPrevious = 0;
int oldNumber;
void setup() {
pinMode(button, INPUT);
Serial.begin(9600);
}
void loop() {
BUTTON = digitalRead(button);
Serial.println(BUTTON);
 if(BUTTON == LOW){
 randomNumber = random(1,4);
 delay(275);
 Serial.print("Random Number ");
 Serial.println(randomNumber);
 if( xPrevious == 0) {
 randomNumber = randomNumber + 1;
 }
 // Only want it to do this on the first roll. 
 xPrevious = randomNumber + xPrevious;
 Serial.print("xPrevious ");
 Serial.println(xPrevious);
 oldNumber = xPrevious;
 for (x = randomNumber; x <= xPrevious; x += 1) { 
 myservo.attach(x);
 Serial.println(x);
 for (pos = 0; pos <= 180; pos += 1) { // goes from 0 degrees to 180 degrees
 //in steps of 1 degree
 myservo.write(pos); // tell servo to go to position in variable 'pos'
 delay(15); // waits 15ms for the servo to reach the position
 }
 for (pos = 180; pos >= 0; pos -= 1) { // goes from 180 degrees to 0 degrees
 myservo.write(pos); // tell servo to go to position in variable 'pos'
 delay(15); // waits 15ms for the servo to reach the position
 }
 }
 }
 }

• duck: Can you explain more? I still don't get the "random" pattern
• mads046: Yeah so it is basically going to be a game where you roll a random number and when you get that number servos will open. For example I roll a 2 on my first time so servo 1,2, and 3 will open. 1 will open because that is where a ball starts. Then on the next turn I roll a 5 so servos 4,5,6,7,8, and 9 open. Does that make more sense?
• duck: if "n" is a random number, the opened servo are servo(0+prevpos+1) through servo(n+prevpos+1)? correct?
• mads046: I think that is it

Answer 1

You planning to use multiple servo, but only declare one. I still don't get about the pattern, but maybe this will give some image:

Servo myservo[5]; // assuming you have 5-servo
 // servo[0]--> pin 0
 // servo[1]--> pin 1
 // servo[2]--> pin 2
 // servo[3]--> pin 3
 // servo[4]--> pin 4
pos = 0;
void loop() {
BUTTON = digitalRead(button);
Serial.println(BUTTON);
 if(BUTTON == LOW){
 randomNumber = random(1,4);
 delay(275);
 pos+=randomNumber;
 Serial.print("Random Number ");
 Serial.println(randomNumber);
 Serial.print("Current pos ");
 Serial.println(pos);
 for (x = 0; x < randomNumber; x++) { 
 myservo[x+pos].attach(x+pos);
 Serial.print("attach servo-");
 Serial.println(x+pos); }
//open (move from 0-180 degrees)
 for (x = 0; x < randomNumber; x++) { 
 myservo[x+pos].write(180);
 }
 delay(2000);
//close (move from 180-0 degrees)
 for (x = 0; x < randomNumber; x++) { 
 myservo[x+pos].write(0);
 }
 delay(2000);
//detach servo
 for (x = 0; x < randomNumber; x++) { 
 myservo[x+pos].detach();
 }
 delay(2000);
}
}