LED pin 13 not flashing properly

Question

This is my first program on Arduino Uno (the starter kit), although I do have prior experience with programming (JavaScript, coding class last year 7th grade). It blinks the internal led (pin 13) in a Morse Code message:

.... . .-.. .-.. --- .-- --- .-. .-.. -..

. = dit(); 
- = dah(); 
(interval between parts of letter) = wip(); 
(interval between letters/words) = wah();

Here's my code:

/*
 * Roman's first program
 * Decipher the message!
*/
int ledPin = 13;
int index = 0;
void setup() {
 //initialize pins as outputs
 pinMode(ledPin, OUTPUT);
 Serial.begin(9600);
}
void loop() {
 int sequence[] = {1,0,1,0,1,0,1,3,1,3,1,0,2,0,1,0,1,3,1,0,2,0,1,0,1,3,2,0,2,0,2,3,3,3,1,0,2,0,2,3,2,0,2,0,2,3,1,0,2,0,1,3,1,0,2,0,1,0,1,3,2,0,1,0,1};
 int arrLength = sizeof(sequence)/sizeof(int); //however THIS works?!
 if (index < arrLength-1) { //0-based array
 index++;
 } else {
 index = 0; //restart the sequence once finished
 }
 if (sequence[index] == 0) {
 wip();
 } else if (sequence[index] == 1) {
 dit();
 } else if (sequence[index] == 2) { 
 dah();
 } else if (sequence[index] == 3) { //because sometimes I the values are screwed past arrLength...
 wah();
 }
 //Serial.println(String(sequence[index])+" , "+String(index));
}
void dit () {
 digitalWrite(pinMode, HIGH); 
 delay(300); 
 digitalWrite(pinMode, LOW);
}
void dah () {
 digitalWrite(pinMode, HIGH); 
 delay(900); 
 digitalWrite(pinMode, LOW);
}
void wip () {
 delay(900);
}
void wah () {
 delay(2100);
}

Yet nothing is happening, except for the four/five startup flashes on the led when I restart it (red button). And yes, I saved and compiled.

Answer 1

Well, mainly digitalWrite(pinMode, HIGH); looks suspicious. I though you called LED pin as ledPin

If you fix this, it should be working. As this one is working too, it's just simplified a little:

int ledPin = 13;
int index = 0;
const int8_t sequence[] = {1,0,1,0,1,0,1,3,1,3,1,0,2,0,1,0,1,3,1,0,2,0,1,0,1,3,2,0,2,0,2,3,3,3,1,0,2,0,2,3,2,0,2,0,2,3,1,0,2,0,1,3,1,0,2,0,1,0,1,3,2,0,1,0,1};
int arrLength = sizeof(sequence);
void setup() {
 pinMode(ledPin, OUTPUT);
 Serial.begin(57600);
}
void loop() {
 Serial.println(String(sequence[index])+" , "+String(index));
 switch (sequence[index++]) {
 case 0: wip(); break;
 case 1: dit(); break;
 case 2: dah(); break;
 case 3: wah(); break;
 }
 if (index == arrLength) {
 index = 0;
 }
}
void dit () {
 digitalWrite(ledPin, HIGH); 
 delay(300); 
 digitalWrite(ledPin, LOW);
}
void dah () {
 digitalWrite(ledPin, HIGH); 
 delay(900); 
 digitalWrite(ledPin, LOW);
}
void wip () {
 delay(900);
}
void wah () {
 delay(2100);
}

• Roman: Thank you! But, I'm pretty new to C code. Could you explain const int8_t or should I learn later? Also, you changed the baud...?
• RubberDuck: @Roman int is likely to be 16 or 32 bits (can't recall off the top of my head). IIRC the size of int may vary depending on the compiler you're using. Using int8_t guarantees an array of 8 bit ints, saving quite a bit of space. You're likely to have plenty of space at first, but eventually you'll write a large program and need to squeeze out every wasted byte you can just to fit it on the mcu.
• JRobert: Specifying 'const' informs the compiler that these variables are not meant to be changed (once initialized) and enables the compiler to check for and enforce that.