BaggerFast / PyConsoleMenu Public

Notifications You must be signed in to change notification settings
Fork 3
Star 11

A simple Python menu in the terminal using curses. Ideal for people who want to quickly make a menu without writing their own complicated crutches. Includes: SelectorMenu, MultipleSelectorMenu, FunctionalMenu.

www.youtube.com/watch?v=jxq9UQrVNq4&t=1s

License

MIT license

11 stars 3 forks Branches Tags Activity

Star

Notifications

BaggerFast/PyConsoleMenu

Branches Tags

Folders and files

Name		Name	Last commit message	Last commit date
Latest commit History 12 Commits
.github/workflows		.github/workflows
PyConsoleMenu		PyConsoleMenu
assets		assets
examples		examples
tests		tests
.gitignore		.gitignore
.pylintrc		.pylintrc
LICENSE.md		LICENSE.md
README.md		README.md
requirements.txt		requirements.txt
setup.cfg		setup.cfg
setup.py		setup.py
tox.ini		tox.ini

Repository files navigation

PyConsoleMenu

CodeFactor BUILD-STATUS

Preview

Selector

See other

Installation 💾

using pip

$ pip install PyConsoleMenu

using GitHub (требуется git)

$ git clone https://github.com/BaggerFast/PyConsoleMenu
$ cd PyConsoleMenu
$ pip install -r requirements.txt

Additionally ⌨️

Docs in code
Type hints

Usage example 👨‍💻

from PyConsoleMenu import MultiSelectorMenu, FunctionalOption, SelectorMenu, FunctionalMenu
def multi_selector():
 menu = MultiSelectorMenu(['Cheburashka', 'Parrot', 'Snake', 'Gena'], title='MultiSelector', count=3)
 ans = menu.input()
 print(ans)
def selector():
 menu = SelectorMenu(['Cheburashka', 'Parrot', 'Snake', 'Gena'], title='Selector')
 ans = menu.input()
 print(ans)
def functional():
 data = [
 FunctionalOption('Cheburashka', lambda: print('I am a Parrot')),
 FunctionalOption('Parrot', lambda: print('I am a Cheburashka')),
 ]
 menu = FunctionalMenu(data, title='Functional')
 ans = menu.input()
 ans()