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std::list<T,Allocator>::pop_front

From cppreference.com
< cpp‎ | container‎ | list
 
 
 
std::list
(until C++20)(until C++20)(until C++20)(until C++20)(until C++20)
 
void pop_front();
(constexpr since C++26)

Removes the first element of the container.

If empty() is true, the behavior is undefined.

(until C++26)

If empty() is true:

  • If the implementation is hardened, a contract violation occurs. Moreover, if the contract-violation handler returns under "observe" evaluation semantic, the behavior is undefined.
  • If the implementation is not hardened, the behavior is undefined.
(since C++26)

References and iterators to the erased element are invalidated.

[edit] Complexity

Constant.

[edit] Example

Run this code
#include <list>
#include <iostream>
 
int main()
{
 std::list <char> chars{'A', 'B', 'C', 'D'};
 
 for (; !chars.empty(); chars.pop_front())
 std::cout << "chars.front(): '" << chars.front() << "'\n";
}

Output:

chars.front(): 'A'
chars.front(): 'B'
chars.front(): 'C'
chars.front(): 'D'

[edit] See also

removes the last element
(public member function) [edit]
inserts an element to the beginning
(public member function) [edit]
access the first element
(public member function) [edit]
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