Saturday, July 7, 2007
Implement the strcpy() function.
Here are some C programs which implement the strcpy() function. This is one of the most frequently asked C interview questions.
Method1
char *mystrcpy(char *dst, const char *src)
{
char *ptr;
ptr = dst;
while(*dst++=*src++);
return(ptr);
}
The strcpy function copies src, including the terminating null character, to the location specified by dst. No overflow checking is performed when strings are copied or appended. The behavior of strcpy is undefined if the source and destination strings overlap. It returns the destination string. No return value is reserved to indicate an error.
Note that the prototype of strcpy as per the C standards is
char *strcpy(char *dst, const char *src);
Notice the const for the source, which signifies that the function must not change the source string in anyway!.
Method2
char *my_strcpy(char dest[], const char source[])
{
int i = 0;
while (source[i] != '0円')
{
dest[i] = source[i];
i++;
}
dest[i] = '0円';
return(dest);
}
Simple, isn't it?
Method1
char *mystrcpy(char *dst, const char *src)
{
char *ptr;
ptr = dst;
while(*dst++=*src++);
return(ptr);
}
The strcpy function copies src, including the terminating null character, to the location specified by dst. No overflow checking is performed when strings are copied or appended. The behavior of strcpy is undefined if the source and destination strings overlap. It returns the destination string. No return value is reserved to indicate an error.
Note that the prototype of strcpy as per the C standards is
char *strcpy(char *dst, const char *src);
Notice the const for the source, which signifies that the function must not change the source string in anyway!.
Method2
char *my_strcpy(char dest[], const char source[])
{
int i = 0;
while (source[i] != '0円')
{
dest[i] = source[i];
i++;
}
dest[i] = '0円';
return(dest);
}
Simple, isn't it?
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18 comments:
If you consider of C Library functions, it takes care of buffer overlapped, Src and Dest can be overlapped.
The purpose of this question is to implement w/o using the std in built libraries
char * strcpy( char *strDest, const char *strSrc )
{
assert( (strDest != NULL) && (strSrc != NULL) );
char *address = strDest;
while( (*strDest++ = * strSrc++) != ‘0円’ );
return address;
}
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Mystrcpy(target,source)
{
*q=*p;
q++;
P++;
}
Sample C Program To Accept A String & Display It.
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Sample C Program To Concatenate Two Strings.
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Sample C Program To Swap Two Strings.
Sample C Program To Swap Two Strings Using strcpy() Function.
Sample C Program To Sort A Given Number Of Strings Using strcmp() Function.
Sample C Program To Check Whether A String Is Palindrome Or Not.
Sample C Program To Print The Reverse Of A String.
Sample C Program To Join Two Strings.
Sample C Program To Display Array Of Strings.
Sample C Program To Convert String To An Integer Using atoi() Function.
Sample C Program To Accept A String & Display In Reverse.
Sample C Program To Accept A String & Display Its Alternate Characters.
Sample C Program To Accept A String & Display Alternate Characters In Either Case.
None of the code says how to allocate memory to the destination.
void stringCopy(Char* source, char* destination)
{
while(*source != 0)
{
*destination = *source;
++source;
++destinaton;
}
*destination = 0;
}
Here's one from K&R[1]
void strcpy(char *s, char*t)
{
while ( *s++ = *t++)
;
}
[1] The C Programming Language, Kernighan & Ritchie
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Hi all,
I'm a pretty young coder.
May a ask you regarding your first method:
char *mystrcpy(char *dst, const char *src)
{
char *ptr;
ptr = dst;
while(*dst++=*src++);
return(ptr);
}
When does the while loop terminate? I thought this would be endless since no checking ='0円' is performed?
Thx in advance!
Very informative article.Thank you author for posting this kind of article .
http://www.wikitechy.com/view-article/string-copy-program-in-c-example-with-explanation
Both are really good,
Cheers,
Venkat
Very informative article.Thank you author for posting this kind of article .
http://www.wikitechy.com/view-article/string-copy-program-in-c-example-with-explanation
Both are really good,
Cheers,
Venkat
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