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std::source_location::line

From cppreference.com
 
 
Utilities library
General utilities
Relational operators (deprecated in C++20)
(C++20)(C++20)(C++20)  
(C++20)
(C++20)
(C++14)
(C++11)
(C++11)
(C++23)
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(C++17)
Common vocabulary types
(C++11)
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constexpr std::uint_least32_t line() const noexcept;
(since C++20)

Returns the line number represented by this object.

[edit] Parameters

(none)

[edit] Return value

The line number represented by this object.

An implementation is encouraged to return 0 when the line number is unknown.

[edit] Example

Run this code
#include <iostream>
#include <string_view>
#include <source_location>
 
inline void cur_line(
 const std::string_view message = "",
 const std::source_location & location = std::source_location::current())
{
 std::cout
 << location.line() // <- the line # of a call site
 << ") "
 << message; 
}
 
int main()
{
 cur_line("++\n");
 cur_line(); std::cout << "Hello,\n";
 cur_line(); std::cout << "C++20!\n";
 cur_line("--\n");
}

Output:

17) ++
18) Hello, 
19) C++20! 
20) --

[edit] See also

return the column number represented by this object
(public member function) [edit]
return the file name represented by this object
(public member function) [edit]
return the name of the function represented by this object, if any
(public member function) [edit]
gets the line number that lexically relates the evaluation represented by the stacktrace_entry
(public member function of std::stacktrace_entry) [edit]
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