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std::chrono::year::operator int

From cppreference.com
< cpp‎ | chrono‎ | year
 
 
Date and time library
(C++11)
(C++20)
(C++11)
(C++11)
(C++11)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)

 
 
constexpr explicit operator int() const noexcept;
(since C++20)

Returns the year value stored in *this.

[edit] Return value

The year value stored in *this.

[edit] Example

Run this code
#include <chrono>
#include <iostream>
using namespace std::chrono;
 
int main()
{
 constexpr std::chrono::year y{2020};
 std::cout << "The year is: " << static_cast<int>(y) << '\n';
 
 const year_month_day ymd{floor<days>(system_clock::now())};
 const std::chrono::year this_year{ymd.year()};
 std::cout << "This year is: " << int(this_year) << '\n';
}

Possible output:

The year is: 2020
This year is: 2023
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