std::quick_exit
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Defined in header
<cstdlib>
[[noreturn]] void quick_exit( int exit_code ) noexcept;
(since C++11)
Causes normal program termination to occur without completely cleaning the resources.
Functions passed to std::at_quick_exit are called in reverse order of their registration. If an exception tries to propagate out of any of the functions, std::terminate is called. After calling the registered functions, calls std::_Exit (exit_code).
Functions passed to std::atexit are not called.
Contents
[edit] Parameters
exit_code
-
exit status of the program
[edit] Return value
(none)
[edit] Example
Run this code
#include <cstdlib> #include <iostream> template<int N> void quick_exit_handler() { std::cout << "quick_exit handler #" << N << std::endl ; // flush is intended } void at_exit_handler() { std::cout << "at_exit handler\n"; } int main() { if (std::at_quick_exit (quick_exit_handler<1>) || std::at_quick_exit (quick_exit_handler<2>)) { std::cerr << "Registration failed\n"; return EXIT_FAILURE ; } std::atexit (at_exit_handler); // the handler will not be called struct R { ~R() { std::cout << "destructor\n"; } } resource; /*...*/ std::quick_exit(EXIT_SUCCESS ); std::cout << "This statement is unreachable...\n"; }
Output:
quick_exit handler #2 quick_exit handler #1
[edit] See also
C documentation for quick_exit