std::chrono::year_month_day_last
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year_month_day_last
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std::chrono::year_month_day_last
Member functions
Nonmember functions
Helper classes
Defined in header
<chrono>
class year_month_day_last;
(since C++20)
The class year_month_day_last represents the last day of a specific year and month. It is a field-based time point, with a resolution of std::chrono::days, subject to the limit that it can only represent the last day of a month.
std::chrono::years- and std::chrono::months-oriented arithmetic are supported directly. An implicit conversion to std::chrono::sys_days allows std::chrono::days-oriented arithmetic to be performed efficiently.
year_month_day_last is a TriviallyCopyable StandardLayoutType.
[edit] Member functions
[edit] Nonmember functions
(C++20)
year_month_day_last and some number of years or months (function) [edit]
[edit] Helper classes
hash support for std::chrono::year_month_day_last
(class template specialization)
(class template specialization)
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { const auto ymd = std::chrono::year_month_day { std::chrono::floor <std::chrono::days >(std::chrono::system_clock::now ()) }; const std::chrono::year_month_day_last ymdl { ymd.year(), ymd.month() / std::chrono::last }; std::cout << "The last day of present month (" << ymdl << ") is: " << std::chrono::year_month_day {ymdl}.day() << '\n'; // The 'last' object can be placed wherever it is legal to place a 'day': using namespace std::chrono; constexpr std::chrono::year_month_day_last ymdl1 = 2023y / February / last, ymdl2 = last / February / 2023y, ymdl3 = February / last / 2023y; static_assert(ymdl1 == ymdl2 && ymdl2 == ymdl3); }
Possible output:
The last day of present month (2023/Aug/last) is: 31