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std::modulus<void>

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< cpp‎ | utility‎ | functional
 
 
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Defined in header <functional>
template<>
class modulus<void>;
(since C++14)

std::modulus <void> is a specialization of std::modulus with parameter and return type deduced.

[edit] Nested types

Nested type Definition
is_transparent unspecified

[edit] Member functions

operator()
returns the modulus of two arguments
(public member function)

std::modulus<void>::operator()

template< class T, class U >

constexpr auto operator()( T&& lhs, U&& rhs ) const

    -> decltype(std::forward <T>(lhs) % std::forward <U>(rhs));

Returns the remainder of the division of lhs by rhs.

Parameters

lhs, rhs - values to divide

Return value

std::forward <T>(lhs) % std::forward <U>(rhs).

[edit] Example

Run this code
#include <functional>
#include <iostream>
 
struct M
{
 M(int x) { std::cout << "M(" << x << ");\n"; }
 M() {}
};
 
auto operator%(M, M) { std::cout << "operator%(M, M);\n"; return M{}; }
auto operator%(M, int) { std::cout << "operator%(M, int);\n"; return M{}; }
auto operator%(int, M) { std::cout << "operator%(int, M);\n"; return M{}; }
 
int main()
{
 M m;
 
 // 42 is converted into a temporary object M{42}
 std::modulus <M>{}(m, 42); // calls operator%(M, M)
 
 // no temporary object
 std::modulus <void>{}(m, 42); // calls operator%(M, int)
 std::modulus <void>{}(42, m); // calls operator%(int, M)
}

Output:

M(42);
operator%(M, M);
operator%(M, int);
operator%(int, M);
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