std::mismatch
(on partitioned ranges)
<algorithm>
std::pair <InputIt1, InputIt2>
mismatch( InputIt1 first1, InputIt1 last1,
std::pair <ForwardIt1, ForwardIt2>
mismatch( ExecutionPolicy&& policy,
ForwardIt1 first1, ForwardIt1 last1,
std::pair <InputIt1, InputIt2>
mismatch( InputIt1 first1, InputIt1 last1,
class ForwardIt1, class ForwardIt2, class BinaryPred >
std::pair <ForwardIt1, ForwardIt2>
mismatch( ExecutionPolicy&& policy,
ForwardIt1 first1, ForwardIt1 last1,
std::pair <InputIt1, InputIt2>
mismatch( InputIt1 first1, InputIt1 last1,
std::pair <ForwardIt1, ForwardIt2>
mismatch( ExecutionPolicy&& policy,
ForwardIt1 first1, ForwardIt1 last1,
std::pair <InputIt1, InputIt2>
mismatch( InputIt1 first1, InputIt1 last1,
class ForwardIt1, class ForwardIt2, class BinaryPred >
std::pair <ForwardIt1, ForwardIt2>
mismatch( ExecutionPolicy&& policy,
ForwardIt1 first1, ForwardIt1 last1,
Returns a pair of iterators to the first mismatching of elements from [
first1,
last1)
and a range starting from first2:
[
first2,
last2)
.
std::is_execution_policy_v <std::decay_t <ExecutionPolicy>> is true.
(until C++20)std::is_execution_policy_v <std::remove_cvref_t <ExecutionPolicy>> is true.
(since C++20)The signature of the predicate function should be equivalent to the following:
bool pred(const Type1 &a, const Type2 &b);
While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1
and Type2
regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for Type1
a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively.
InputIt1
must meet the requirements of LegacyInputIterator.
InputIt2
must meet the requirements of LegacyInputIterator.
ForwardIt1
must meet the requirements of LegacyForwardIterator.
ForwardIt2
must meet the requirements of LegacyForwardIterator.
BinaryPred
must meet the requirements of BinaryPredicate.
std::pair with iterators to the first two non-equal elements.
If last1 is reached, the second iterator in the pair is the std::distance (first1, last1)th iterator after first2.
For overloads (5-8), if last2 is reached, the first iterator in the pair is the std::distance (first2, last2)th iterator after first1.
Given \(\scriptsize N_1\)N1 as std::distance (first1, last1) and \(\scriptsize N_2\)N2 as std::distance (first2, last2):
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any other ExecutionPolicy
, the behavior is implementation-defined.
mismatch (1) |
---|
template<class InputIt1, class InputIt2> std::pair <InputIt1, InputIt2> mismatch(InputIt1 first1, InputIt1 last1, InputIt2 first2) { while (first1 != last1 && *first1 == *first2) ++first1, ++first2; return std::make_pair (first1, first2); } |
mismatch (3) |
template<class InputIt1, class InputIt2, class BinaryPred> std::pair <InputIt1, InputIt2> mismatch(InputIt1 first1, InputIt1 last1, InputIt2 first2, BinaryPred p) { while (first1 != last1 && p(*first1, *first2)) ++first1, ++first2; return std::make_pair (first1, first2); } |
mismatch (5) |
template<class InputIt1, class InputIt2> std::pair <InputIt1, InputIt2> mismatch(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2) { while (first1 != last1 && first2 != last2 && *first1 == *first2) ++first1, ++first2; return std::make_pair (first1, first2); } |
mismatch (7) |
template<class InputIt1, class InputIt2, class BinaryPred> std::pair <InputIt1, InputIt2> mismatch(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, BinaryPred p) { while (first1 != last1 && first2 != last2 && p(*first1, *first2)) ++first1, ++first2; return std::make_pair (first1, first2); } |
This program determines the longest substring that is simultaneously found at the very beginning of the given string and at the very end of it, in reverse order (possibly overlapping).
#include <algorithm> #include <iostream> #include <string> std::string mirror_ends(const std::string & in) { return std::string (in.begin(), std::mismatch(in.begin(), in.end(), in.rbegin()).first); } int main() { std::cout << mirror_ends("abXYZba") << '\n' << mirror_ends("abca") << '\n' << mirror_ends("aba") << '\n'; }
Output:
ab a aba