template< class InputIt, class ForwardIt >
InputIt find_first_of( InputIt first, InputIt last,
ForwardIt s_first, ForwardIt s_last );
(1)
(constexpr since C++20)
template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 >
ForwardIt1 find_first_of( ExecutionPolicy&& policy,
ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last );
(2)
(since C++17)
template< class InputIt, class ForwardIt, class BinaryPred >
InputIt find_first_of( InputIt first, InputIt last,
ForwardIt s_first, ForwardIt s_last,
BinaryPred p );
(3)
(constexpr since C++20)
template< class ExecutionPolicy,
class ForwardIt1, class ForwardIt2, class BinaryPred >
ForwardIt1 find_first_of( ExecutionPolicy&& policy,
ForwardIt1 first, ForwardIt last,
ForwardIt2 s_first, ForwardIt2 s_last,
BinaryPred p );
(4)
(since C++17)
Searches the range [first, last) for any of the elements in the range [s_first, s_last).
1) Elements are compared using operator==.
3) Elements are compared using the given binary predicate p.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if all following conditions are satisfied:
[edit] Parameters
first, last
-
the pair of iterators defining the
range of elements to examine
s_first, s_last
-
the pair of iterators defining the
range of elements to search for
p
-
binary predicate which returns
true if the elements should be treated as equal.
The signature of the predicate function should be equivalent to the following:
bool pred(const Type1 &a, const Type2 &b);
While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1 and Type2 regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for Type1 a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that objects of types ForwardIt1 and ForwardIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively.
Type requirements
[edit] Return value
Iterator to the first element in the range [first, last) that is equal to an element from the range [s_first, s_last).
If [s_first, s_last) is empty or if no such element is found, last is returned.
[edit] Complexity
Given \(\scriptsize N\)N as std::distance (first, last) and \(\scriptsize S\)S as std::distance (s_first, s_last):
1,2) At most \(\scriptsize N\cdot S\)N·S comparisons using operator==.
3,4) At most \(\scriptsize N\cdot S\)N·S applications of the predicate p.
[edit] Exceptions
The overloads with a template parameter named ExecutionPolicy report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy is one of the standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
- If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit] Possible implementation
| find_first_of (1)
|
template<class InputIt, class ForwardIt>
InputIt find_first_of(InputIt first, InputIt last,
ForwardIt s_first, ForwardIt s_last)
{
for (; first != last; ++first)
for (ForwardIt it = s_first; it != s_last; ++it)
if (*first == *it)
return first;
return last;
} |
| find_first_of (3)
|
template<class InputIt, class ForwardIt, class BinaryPred>
InputIt find_first_of(InputIt first, InputIt last,
ForwardIt s_first, ForwardIt s_last,
BinaryPred p)
{
for (; first != last; ++first)
for (ForwardIt it = s_first; it != s_last; ++it)
if (p(*first, *it))
return first;
return last;
} |
[edit] Example
The following code searches for any of specified integers in a vector of integers:
#include <algorithm>
#include <iostream>
#include <vector>
auto print_sequence = [](const auto id, const auto& seq, int pos = -1)
{
std::cout << id << "{ ";
for (int i{}; auto const& e : seq)
{
const bool mark{i == pos};
std::cout << (i++ ? ", " : "");
std::cout << (mark ? "[ " : "") << e << (mark ? " ]" : "");
}
std::cout << " }\n";
};
int main()
{
const std::vector <int> v{0, 2, 3, 25, 5};
const auto t1 = {19, 10, 3, 4};
const auto t2 = {1, 6, 7, 9};
auto find_any_of = [](const auto& v, const auto& t)
{
const auto result = std::find_first_of(v.begin(), v.end(),
t.begin(), t.end());
if (result == v.end())
{
std::cout << "No elements of v are equal to any element of ";
print_sequence("t = ", t);
print_sequence("v = ", v);
}
else
{
const auto pos = std::distance (v.begin(), result);
std::cout << "Found a match (" << *result << ") at position " << pos;
print_sequence(", where t = ", t);
print_sequence("v = ", v, pos);
}
};
find_any_of(v, t1);
find_any_of(v, t2);
}Output:
Found a match (3) at position 2, where t = { 19, 10, 3, 4 }
v = { 0, 2, [ 3 ], 25, 5 }
No elements of v are equal to any element of t = { 1, 6, 7, 9 }
v = { 0, 2, 3, 25, 5 }[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
[edit] See also
finds the first element satisfying specific criteria
(function template) [edit]
searches for any one of a set of elements
(algorithm function object)[edit]