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std::chrono::time_point<Clock,Duration>::min

From cppreference.com
< cpp‎ | chrono‎ | time point
 
 
Date and time library
(C++11)
(C++20)
(C++11)
(C++11)
(C++11)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)(C++20)
(C++20)
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(C++20)

 
 
static constexpr time_point min();
(until C++20)
static constexpr time_point min() noexcept;
(since C++20)

Returns a time_point with the smallest possible duration, i.e. time_point(duration::min()).

[edit] Parameters

(none)

[edit] Return value

The smallest possible time_point.

[edit] Example

Run this code
#include <chrono>
#include <iomanip>
#include <iostream>
#include <ratio>
#include <string>
 
constexpr auto steady_min = std::chrono::steady_clock::time_point::min();
 
void animate_frame_at_time_offset(double game_time)
{
 std::cout << std::string (static_cast<int>(game_time) % 10 + 1, '*') << '\n';
}
 
int main()
{
 auto last_frame = steady_min;
 std::chrono::duration <double, std::micro > game_time{0.0};
 
 for (int n = 0; n < 5; ++n)
 {
 const auto current_frame = std::chrono::steady_clock::now ();
 // initialize timer if first frame ever:
 if (last_frame == steady_min)
 last_frame = current_frame;
 game_time += current_frame - last_frame;
 std::cout << "Drawing frame at " << std::setprecision (10)
 << std::setw (8) << game_time.count() << " μs ";
 animate_frame_at_time_offset(game_time.count());
 }
}

Possible output:

Drawing frame at 0 μs *
Drawing frame at 134.499 μs *****
Drawing frame at 274.337 μs *****
Drawing frame at 416.571 μs *******
Drawing frame at 561.124 μs **
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