Issue 28952: csv.Sniffer().sniff(0) returns a value without the "strict" attribute

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This issue has been migrated to GitHub: https://github.com/python/cpython/issues/73138

classification

Title:	csv.Sniffer().sniff(0) returns a value without the "strict" attribute
Type:	behavior	Stage:
Components:	Library (Lib)	Versions:	Python 3.5

process

Dependencies:	Superseder:
Status:	open	Resolution:
Assigned To:	Nosy List:	4Dummies
Priority:	normal	Keywords:

Created on 2016年12月12日 19:38 by 4Dummies, last changed 2022年04月11日 14:58 by admin.

Messages (1)
msg283041 - (view)	Author: kevin (4Dummies)	Date: 2016年12月12日 19:38
In https://docs.python.org/3.5/library/csv.html#dialects-and-formatting-parameters the Dialect objects are described as supporting, among others, the Dialect.strict attribute, with a default value of False. However, the sniff() returns an object lacking this attribute entirely, not even with the value None. At least on my inputs, which I'd include but they have personnel information. I can redact it if required.

Messages (1)

msg283041 - (view)

Author: kevin (4Dummies)

Date: 2016年12月12日 19:38

In 
 https://docs.python.org/3.5/library/csv.html#dialects-and-formatting-parameters 
the Dialect objects are described as supporting, among others, the Dialect.strict attribute, with a default value of False. However, the
sniff() returns an object lacking this attribute entirely, not even with the value None. At least on my inputs, which I'd include but they have personnel information. I can redact it if required.

History
Date	User	Action	Args
2022年04月11日 14:58:40	admin	set	github: 73138
2017年01月02日 02:49:54	ppperry	set	title: csv.Sniffer().sniff(0 returns a value without the "strict" attribute -> csv.Sniffer().sniff(0) returns a value without the "strict" attribute
2016年12月12日 19:38:54	4Dummies	create

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