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Summary: |
A method without an in contract should always succeed, even if overridden |
Product: |
D
|
Reporter: |
Kazuhiro Inaba <kiki> |
Component: |
dmd | Assignee: |
No Owner <nobody> |
Status: |
RESOLVED
FIXED
|
Severity: |
normal
|
CC: |
bugzilla, yebblies
|
Priority: |
P2
|
Keywords: |
patch, wrong-code |
Version: |
D2 |
Hardware: |
All |
OS: |
All |
In dmd 2.039, the following code fails to pass the in-contract.
class Base
{
void method() {}
}
class Derived : Base
{
void method() in { assert(false); } body {}
}
void main()
{
Base b = new Derived;
b.method();
}
But, according to the spec, IIUC, it should successfully pass the check.
> A function without an in contract means that any values of the function parameters are allowed. This implies that if any function in an inheritance hierarchy has no in contract, then in contracts on functions overriding it have no useful effect.
If I add an explicit empty in-contract to Base.method:
void method() in{} body{}
then it passes the check.