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Day 5 Level 1 Q14
#772
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let itCompanies = [ "Facebook", "Google", "Microsoft", "Apple", "IBM", "Oracle", "Amazon" ] // Filter out companies which have more than one 'o' without the filter method
I solve it with the For loop, something like this
let filtered_array = []; for(i = 0; i < itCompanies.length; i++) { let thing = itCompanies[i]; if(thing.indexOf("o") !== thing.lastIndexOf("o")){ filtered_array.push(thing); } } console.log(filtered_array) // [ 'Facebook', 'Google', 'Microsoft' ]
The problem is that the loop stuff would first appear in the course on Day 6, while this is a question in the Day 5 exercise. So, I wonder if there is a solution that does not involve either the filter method or the loop.
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Replies: 2 comments
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So all we just have to do is when you a question and it so confusing just
leave it blank and move on with the next one then come back to that
question again when you have more confidence.
... On Sat, 3 Jun 2023, 19:06 Harufuu, ***@***.***> wrote:
let itCompanies = [
"Facebook",
"Google",
"Microsoft",
"Apple",
"IBM",
"Oracle",
"Amazon"
]// Filter out companies which have more than one 'o' without the filter method
I solve it with the For loop, something like this
let filtered_array = [];for(i = 0; i < itCompanies.length; i++) {
let thing = itCompanies[i];
if(thing.indexOf("o") !== thing.lastIndexOf("o")){
filtered_array.push(thing);
}}
console.log(filtered_array) // [ 'Facebook', 'Google', 'Microsoft' ]
The problem is that the loop stuff would first appear in the course on Day
6, while this is a question in the Day 5 exercise. So, I wonder if there is
a solution that does not involve either the filter method or the loop.
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@Harufuu Here, it may help you.
let itCompanies = ['facebook', 'google', 'microsoft', .....]
var newArray = []
itCompanies.map((v,i)=>{
if(v.includes('o')){
newArray.push(v);
}
})
console.log(newArray); // [items with o will be added here.]
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