@s mod and
\let\Xmod=\bmod % this is CWEB magic for using "mod" instead of "%"
\font\boldital=cmbxti10
\datethis
@*Intro. This program is an ``{\mc XCC} solver'' that I'm writing
as an experiment in the use of so-called sparse-set data structures
instead of the dancing links structures that I've played with for thirty years.
I plan to write it as if I live on a planet where the sparse-set
ideas are well known, but doubly linked links are almost unheard-of.
The difference between this program and {\mc SSXCC}, on which it's based,
is that I use binary branching `$i=o$' versus `$i\ne o$' at each step,
where $i$ is an item and $o$ is an option,
while {\mc SSXCC} does $d$-way branching on all $d$ options that
currently cover item~$i$. The reason for binary branching is that
I plan to extend this program in various ways, in order to experiment
with several dynamic branching heuristics that I've seen in the literature;
those heuristics were designed with binary branching in mind.
I suggest that you read {\mc SSXCC} first.
After this program finds all solutions, it normally prints their total
number on |stderr|, together with statistics about how many
nodes were in the search tree, and how many ``updates'' were made.
The running time in ``mems'' is also reported, together with the approximate
number of bytes needed for data storage.
(An ``update'' is the removal of an option from its item list,
or the removal of a satisfied color constraint from its option.
One ``mem'' essentially means a memory access to a 64-bit word.
The reported totals don't include the time or space needed to parse the
input or to format the output.)
@d o mems++ /* count one mem */
@d oo mems+=2 /* count two mems */
@d ooo mems+=3 /* count three mems */
@d subroutine_overhead mems+=4
@d O "%" /* used for percent signs in format strings */
@d mod % /* used for percent signs denoting remainder in \CEE/ */
@#
@d max_stage 500 /* at most this many options in a solution */
@d max_level 32000 /* at most this many levels in the search tree */
@d max_cols 100000 /* at most this many items */
@d max_nodes 10000000 /* at most this many nonzero elements in the matrix */
@d savesize 10000000 /* at most this many entries on |savestack| */
@d bufsize (9*max_cols+3) /* a buffer big enough to hold all item names */
@#
@d show_basics 1 /* |vbose| code for basic stats; this is the default */
@d show_choices 2 /* |vbose| code for backtrack logging */
@d show_details 4 /* |vbose| code for further commentary */
@d show_record_weights 16 /* |vbose| code for first time a weight appears */
@d show_weight_bumps 32 /* |vbose| code to show new weights */
@d show_final_weights 64 /* |vbose| code to display weights at the end */
@d show_profile 128 /* |vbose| code to show the search tree profile */
@d show_full_state 256 /* |vbose| code for complete state reports */
@d show_tots 512 /* |vbose| code for reporting item totals at start */
@d show_warnings 1024 /* |vbose| code for reporting options without primaries */
@d show_max_deg 2048 /* |vbose| code for reporting maximum branching degree */
@ Here is the overall structure:
@c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include "gb_flip.h"
typedef unsigned int uint; /* a convenient abbreviation */
typedef unsigned long long ullng; /* ditto */
@<type definitions@>;
@<global variables@>;
@<subroutines@>;
main (int argc, char *argv[]) {
 register int c,cc,i,j,k,p,pp,q,r,s,t,cur_choice,cur_node,best_itm;
 @<process the command line@>;
 @<input the item names@>;
 @<input the options@>;
 if (vbose&show_basics)
 @<report the successful completion of the input phase@>;
 if (vbose&show_tots)
 @<report the item totals@>;
 imems=mems, mems=0;
 if (baditem) @<report an uncoverable item@>@;
 else {
 if (randomizing) @<randomize the &#124;item&#124; list@>;
 @<solve the problem@>;
 }
done:@+if (vbose&show_profile) @<print the profile@>;
 if (vbose&show_final_weights) {
 fprintf(stderr,"Final weights:\n");
 print_weights();
 }
 if (vbose&show_max_deg)
 fprintf(stderr,"The maximum best_itm size was "O"d.\n",maxdeg);
 if (vbose&show_basics) {
 fprintf(stderr,"Altogether "O"llu solution"O"s, "O"llu+"O"llu mems,",
 count,count==1?"":"s",imems,mems);
 bytes=(itemlength+setlength)*sizeof(int)+last_node*sizeof(node)
 +2*maxl*sizeof(int)+maxsaveptr*sizeof(twoints);
 fprintf(stderr," "O"llu updates, "O"llu bytes, "O"llu nodes,",
 updates,bytes,nodes);
 fprintf(stderr," ccost "O"lld%%.\n",
 mems? (200*cmems+mems)/(2*mems):0);
 }
 if (sanity_checking) fprintf(stderr,"sanity_checking was on!\n");
 @<close the files@>;
}
@ You can control the amount of output, as well as certain properties
of the algorithm, by specifying options on the command line:
\smallskip\item{$\bullet$}
`\.v$\langle,円$integer$,円\rangle$' enables or disables various kinds of verbose
 output on &#124;stderr&#124;, given by binary codes such as &#124;show_choices&#124;;
\item{$\bullet$}
`\.m$\langle,円$integer$,円\rangle$' causes every $m$th solution
to be output (the default is \.{m0}, which merely counts them);
\item{$\bullet$}
`\.s$\langle,円$integer$,円\rangle$' causes the algorithm to randomize
the initial list of items (thus providing some variety, although
the solutions are by no means uniformly random);
\item{$\bullet$}
`\.d$\langle,円$integer$,円\rangle$' sets &#124;delta&#124;, which causes periodic
state reports on &#124;stderr&#124; after the algorithm has performed approximately
&#124;delta&#124; mems since the previous report (default 10000000000);
\item{$\bullet$}
`\.c$\langle,円$positive integer$,円\rangle$' limits the levels on which
choices are shown during verbose tracing;
\item{$\bullet$}
`\.C$\langle,円$positive integer$,円\rangle$' limits the levels on which
choices are shown in the periodic state reports (default 10);
\item{$\bullet$}
`\.l$\langle,円$nonnegative integer$,円\rangle$' gives a {\it lower\/} limit,
relative to the maximum level so far achieved, to the levels on which
choices are shown during verbose tracing;
\item{$\bullet$}
`\.t$\langle,円$positive integer$,円\rangle$' causes the program to
stop after this many solutions have been found;
\item{$\bullet$}
`\.T$\langle,円$integer$,円\rangle$' sets &#124;timeout&#124; (which causes abrupt
termination if &#124;mems>timeout&#124; at the beginning of a level);
\item{$\bullet$}
`\.w$\langle,円$float$,円\rangle$' is the initial increment &#124;dw&#124; added to
an item's weight (default 1.0);
\item{$\bullet$}
`\.W$\langle,円$float$,円\rangle$' is the factor by which &#124;dw&#124; changes
dynamically (default 1.0);
\item{$\bullet$}
`\.S$\langle,円$filename$,円\rangle$' to output a ``shape file'' that encodes
the search tree.
@<glob...@>=
int random_seed=0; /* seed for the random words of &#124;gb_rand&#124; */
int randomizing; /* has `\.s' been specified? */
int vbose=show_basics+show_warnings; /* level of verbosity */
int spacing; /* solution $k$ is output if $k$ is a multiple of &#124;spacing&#124; */
int show_choices_max=1000000; /* above this level, &#124;show_choices&#124; is ignored */
int show_choices_gap=1000000; /* below level &#124;maxl-show_choices_gap&#124;,
 &#124;show_details&#124; is ignored */
int show_levels_max=10; /* above this level, state reports stop */
int maxl; /* maximum level actually reached */
int maxs; /* maximum stage actually reached */
int maxsaveptr; /* maximum size of &#124;savestack&#124; */
char buf[bufsize]; /* input buffer */
ullng count; /* solutions found so far */
ullng options; /* options seen so far */
ullng imems,mems,tmems,cmems; /* mem counts */
ullng updates; /* update counts */
ullng bytes; /* memory used by main data structures */
ullng nodes; /* total number of branch nodes initiated */
ullng thresh=10000000000; /* report when &#124;mems&#124; exceeds this, if &#124;delta!=0&#124; */
ullng delta=10000000000; /* report every &#124;delta&#124; or so mems */
ullng maxcount=0xffffffffffffffff; /* stop after finding this many solutions */
ullng timeout=0x1fffffffffffffff; /* give up after this many mems */
float w0=1.0,dw=1.0,dwfactor=1.0; /* initial weight, increment, and growth */
float maxwt=1.0; /* largest weight seen so far */
FILE *shape_file; /* file for optional output of search tree shape */
char *shape_name; /* its name */
int maxdeg; /* the largest branching degree seen so far */
@ If an option appears more than once on the command line, the first
appearance takes precedence.
@<process the command line@>=
for (j=argc-1,k=0;j;j--) switch (argv[j][0]) {
case 'v': k&#124;=(sscanf(argv[j]+1,""O"d",&vbose)-1);@+break;
case 'm': k&#124;=(sscanf(argv[j]+1,""O"d",&spacing)-1);@+break;
case 's': k&#124;=(sscanf(argv[j]+1,""O"d",&random_seed)-1),randomizing=1;@+break;
case 'd': k&#124;=(sscanf(argv[j]+1,""O"lld",&delta)-1),thresh=delta;@+break;
case 'c': k&#124;=(sscanf(argv[j]+1,""O"d",&show_choices_max)-1);@+break;
case 'C': k&#124;=(sscanf(argv[j]+1,""O"d",&show_levels_max)-1);@+break;
case 'l': k&#124;=(sscanf(argv[j]+1,""O"d",&show_choices_gap)-1);@+break;
case 't': k&#124;=(sscanf(argv[j]+1,""O"lld",&maxcount)-1);@+break;
case 'T': k&#124;=(sscanf(argv[j]+1,""O"lld",&timeout)-1);@+break;
case 'w': k&#124;=(sscanf(argv[j]+1,""O"f",&dw)-1);@+break;
case 'W': k&#124;=(sscanf(argv[j]+1,""O"f",&dwfactor)-1);@+break;
case 'S': shape_name=argv[j]+1, shape_file=fopen(shape_name,"w");
 if (!shape_file)
 fprintf(stderr,"Sorry, I can't open file `"O"s' for writing!\n",
 shape_name);
 break;
default: k=1; /* unrecognized command-line option */
}
if (k) {
 fprintf(stderr, "Usage: "O"s [v<n>] [m<n>] [s<n>] [d<n>]"
 " [c<n>] [C<n>] [l<n>] [t<n>] [T<n>] [w<f>] [W<f>] [S<bar>] < foo.dlx\n", argv[0]); exit(-1); } if (randomizing) gb_init_rand(random_seed); @ @<close the files@>=
if (shape_file) fclose(shape_file);
@ Here's a subroutine that I hope is never invoked (except maybe
when I'm debugging).
@<sub...@>=
void confusion(char*m) {
 fprintf(stderr,""O"s!\n",m);
}
@*Data structures.
Sparse-set data structures were introduced by Preston Briggs
and Linda Torczon [{\sl ACM Letters on Programming Languages and Systems\/
\bf2} (1993), 59--69], who realized that exercise 2.12 in
Aho, Hopcroft, and Ullman's classic text {\sl The Design and Analysis
of Computer Algorithms\/} (Addison--Wesley, 1974) was much more than
just a slick trick to avoid initializing an array.
(Indeed, {\sl TAOCP\/} exercise 2.2.6--24 calls it the ``sparse array trick.'')
The basic idea is amazingly simple, when specialized to the situations
that we need to deal with: We can represent a subset~$S$ of the universe
$U=\{x_0,x_1,\ldots,x_{n-1}\}$ by maintaining two $n$-element arrays
$p$ and $q,ドル each of which is a permutation of~$\{0,1,\ldots,n-1\},ドル
together with an integer $s$ in the range 0ドル\le s\le n$. In fact, $p$ is
the {\it inverse\/} of~$q$; and $s$ is the number of elements of~$S$.
The current value of the set $S$ is then simply
$\{x_{p_0},\ldots,x_{p_{s-1}}\}$. (Notice that every $s$-element subset can be
represented in $s!,円(n-s)!$ ways.)
It's easy to test if $x_k\in S,ドル because that's true if and only if $q_k<s$. It's easy to insert a new element $x_k$ into~$S$: Swap indices so that $p_s=k,ドル $q_k=s,ドル then increase $s$ by~1. It's easy to delete an element $x_k$ that belongs to~$S$: Decrease $s$ by~1, then swap indices so that $p_s=k$ and $q_k=s$. And so on. Briggs and Torczon were interested in applications where $s$ begins at zero and tends to remain small. In such cases, $p$ and $q$ need not be permutations: The values of $p_s,ドル $p_{s+1},ドル \dots, $p_{n-1}$ can be garbage, and the values of $q_k$ need be defined only when $x_k\in S$. (Such situations correspond to the treatment by Aho, Hopcroft, and Ullman, who started with an array full of garbage and used a sparse-set structure to remember the set of nongarbage cells.) Our applications are different: Each set begins equal to its intended universe, and gradually shrinks. In such cases, we might as well maintain inverse permutations. The basic operations go faster when we know in advance that we aren't inserting an element that's already present (nor deleting an element that isn't). Many variations are possible. For example, $p$ could be a permutation of $\{x_0,x_1,\ldots,x_{n-1}\}$ instead of a permutation of $\{0,1,\ldots,n-1\}$. The arrays that play the role of $q$ in the following routines don't have indices that are consecutive; they live inside of other structures. @ This program has an array called &#124;item&#124;, with one entry for each item. The value of &#124;item[k]&#124; is an index~&#124;x&#124; into a much larger array called &#124;set&#124;. The set of all options that involve the $k$th item appears in that array beginning at &#124;set[x]&#124;; and it continues for $s$ consecutive entries, where &#124;s=size(x)&#124; is an abbreviation for &#124;set[x-1]&#124;. If &#124;item[k]=x&#124;, we maintain the relation &#124;pos(x)=k&#124;, where &#124;pos(x)&#124; is an abbreviation for &#124;set[x-2]&#124;. Thus &#124;item&#124; plays the role of array~$p,ドル in a sparse-set data structure for the set of all currently active items; and &#124;pos&#124; plays the role of~$q$. A primary item $x$ also has a &#124;wt&#124; field, &#124;set[x-5]&#124;, initially~1. The weight is increased by &#124;dw&#124; whenever we backtrack because &#124;x&#124; cannot be covered. (Weights aren't actually {\it used} in the present program; that will come in extensions to be written later. But it will be convenient to have space ready for them in our data structures, so that those extensions will be easy to write.) Suppose the &#124;k&#124;th item &#124;x&#124; currently appears in &#124;s&#124; options. Those options are indices into &#124;nd&#124;, which is an array of ``nodes.'' Each node has three fields: &#124;itm&#124;, &#124;loc&#124;, and &#124;clr&#124;. If &#124;x<=q<x+s&#124;, let &#124;y=set[q]&#124;. This is essentially a pointer to a node, and we have &#124;nd[y].itm=x&#124;, &#124;nd[y].loc=q&#124;. In other words, the sequential list of &#124;s&#124; elements that begins at &#124;x=item[k]&#124; in the &#124;set&#124; array is the sparse-set representation of the currently active options that contain the &#124;k&#124;th item. The &#124;clr&#124; field &#124;nd[y].clr&#124; contains &#124;x&#124;'s color for this option. The &#124;itm&#124; and &#124;clr&#124; fields remain constant, once we've initialized everything, but the &#124;loc&#124; fields will change. The given options are stored sequentially in the &#124;nd&#124; array, with one node per item, separated by ``spacer'' nodes. If &#124;y&#124; is the spacer node following an option with $t$ items, we have &#124;nd[y].itm=-t&#124;. If &#124;y&#124; is the spacer node {\it preceding\/} an option with $t$ items, we have &#124;nd[y].loc=t&#124;. This probably sounds confusing, until you can see some code. Meanwhile, let's take note of the invariant relations that hold whenever &#124;k&#124;, &#124;q&#124;, &#124;x&#124;, and &#124;y&#124; have appropriate values: $$\hbox{&#124;pos(item[k])=k&#124;;\quad &#124;nd[set[q]].loc=q&#124;;\quad &#124;item[pos(x)]=x&#124;;\quad &#124;set[nd[y].loc]=y&#124;.}$$ (These are the analogs of the invariant relations &#124;p[q[k]]=q[p[k]]=k&#124; in the simple sparse-set scheme that we started with.) The &#124;set&#124; array contains also the item names. We count one mem for a simultaneous access to the &#124;itm&#124; and &#124;loc&#124; fields of a node. Each node actually has a ``spare'' fourth field, &#124;spr&#124;, inserted solely to enforce alignment to 16-byte boundaries. (Some modification of this program might perhaps have a use for &#124;spr&#124;?) @d size(x) set[(x)-1].i /* number of active options of the &#124;k&#124;th item, &#124;x&#124; */ @d pos(x) set[(x)-2].i /* where that item is found in the &#124;item&#124; array, &#124;k&#124; */ @d lname(x) set[(x)-4].i /* the first four bytes of &#124;x&#124;'s name */ @d rname(x) set[(x)-3].i /* the last four bytes of &#124;x&#124;'s name */ @d wt(x) set[(x)-5].f /* the current floating-point ``weight'' of &#124;x&#124; */ @d primextra 5 /* this many extra entries of &#124;set&#124; for each primary item */ @d secondextra 4 /* and this many for each secondary item */ @d maxextra 5 /* maximum of &#124;primextra&#124; and &#124;secondextra&#124; */ @<type...@>=
typedef struct node_struct {
 int itm; /* the item &#124;x&#124; corresponding to this node */
 int loc; /* where this node resides in &#124;x&#124;'s active set */
 int clr; /* color associated with item &#124;x&#124; in this option, if any */
 int spr; /* a spare field inserted only to maintain 16-byte alignment */
} node;
typedef union {
 int i; /* an integer (32 bits) */
 float f; /* a floating point value (fits in 4 bytes) */
} tetrabyte;
@ @<glob...@>=
node nd[max_nodes]; /* the master list of nodes */
int last_node; /* the first node in &#124;nd&#124; that's not yet used */
int item[max_cols]; /* the master list of items */
int second=max_cols; /* boundary between primary and secondary items */
int last_itm; /* items seen so far during input, plus 1 */
tetrabyte set[max_nodes+maxextra*max_cols]; /* active options for active items */
int itemlength; /* number of elements used in &#124;item&#124; */
int setlength; /* number of elements used in &#124;set&#124; */
int active; /* current number of active items */
int baditem; /* an item with no options, plus 1 */
int osecond; /* setting of &#124;second&#124; just after initial input */
int force[max_cols]; /* stack of items known to have size 1 */
int forced; /* the number of items on that stack */
@ We're going to store string data (an item's name) in the midst of
the integer array &#124;set&#124;. So we've got to do some type coercion using
low-level \CEE/-ness.
@<type def...@>=
typedef struct {
 int l,r;
} twoints;
typedef union {
 unsigned char str[8]; /* eight one-byte characters */
 twoints lr; /* two four-byte integers */
} stringbuf;
stringbuf namebuf;
@ @<subroutines@>=
void print_item_name(int k,FILE *stream) {
 namebuf.lr.l=lname(k),namebuf.lr.r=rname(k);
 fprintf(stream," "O".8s",namebuf.str);
}
@ An option is identified not by name but by the names of the items it contains.
Here is a routine that prints an option, given a pointer to any of its
nodes. It also prints the position of the option in its item list.
@<sub...@>=
void print_option(int p,FILE *stream,int showpos) {
 register int k,q,x;
 x=nd[p].itm;
 if (p>=last_node &#124;&#124; x<=0) { fprintf(stderr,"Illegal option "O"d!\n",p); return; } for (q=p;;) { print_item_name(x,stream); if (nd[q].clr) fprintf(stream,":"O"c",nd[q].clr); q++; x=nd[q].itm; if (x<0) q+=x,x=nd[q].itm; if (q==p) break; } k=nd[q].loc; if (showpos>0) fprintf(stream," ("O"d of "O"d)\n",k-x+1,size(x));
 else if (showpos==0) fprintf(stream,"\n");
}
@#
void prow(int p) {
 print_option(p,stderr,1);
}
@ When I'm debugging, I might want to look at one of the current item lists.
@<sub...@>=
void print_itm(int c) {
 register int p;
 if (c<primextra &#124;&#124; c>=setlength &#124;&#124;
 pos(c)<0 &#124;&#124; pos(c)>=itemlength &#124;&#124; item[pos(c)]!=c) {
 fprintf(stderr,"Illegal item "O"d!\n",c);
 return;
 }
 fprintf(stderr,"Item");
 print_item_name(c,stderr);
 if (c<second) fprintf(stderr," ("O"d of "O"d), length "O"d, weight "O".1f:\n", pos(c)+1,active,size(c),wt(c)); else if (pos(c)>=active)
 fprintf(stderr," (secondary "O"d, purified), length "O"d:\n",
 pos(c)+1,size(c));
 else fprintf(stderr," (secondary "O"d), length "O"d:\n",
 pos(c)+1,size(c));
 for (p=c;p<c+size(c);p++) prow(set[p].i); } @ Speaking of debugging, here's a routine to check if redundant parts of our data structure have gone awry. @d sanity_checking 0 /* set this to 1 if you suspect a bug */ @<sub...@>=
void sanity(void) {
 register int k,x,i,l,r,q,qq;
 for (k=0;k<itemlength;k++) { x=item[k]; if (pos(x)!=k) { fprintf(stderr,"Bad pos field of item"); print_item_name(x,stderr); fprintf(stderr," ("O"d,"O"d)!\n",k,x); } } for (i=0;i<last_node;i++) { l=nd[i].itm,r=nd[i].loc; if (l<=0) { if (nd[i+r+1].itm!=-r) fprintf(stderr,"Bad spacer in nodes "O"d, "O"d!\n",i,i+r+1); qq=0; }@+else { if (l>r) fprintf(stderr,"itm>loc in node "O"d!\n",i);
 else {
 if (set[r].i!=i) {
 fprintf(stderr,"Bad loc field for option "O"d of item",r-l+1);
 print_item_name(l,stderr);
 fprintf(stderr," in node "O"d!\n",i);
 }
 if (pos(l)<active) { if (r<l+size(l)) q=+1;@+else q=-1; /* in or out? */ if (q*qq<0) { fprintf(stderr,"Flipped status at option "O"d of item",r-l+1); print_item_name(l,stderr); fprintf(stderr," in node "O"d!\n",i); } qq=q; } } } } } @*Inputting the matrix. Brute force is the rule in this part of the code, whose goal is to parse and store the input data and to check its validity. We use only four entries of &#124;set&#124; per item while reading the item-name line. @d panic(m) {@+fprintf(stderr,""O"s!\n"O"d: "O".99s\n",m,p,buf);@+exit(-666);@+} @<input the item names@>=
while (1) {
 if (!fgets(buf,bufsize,stdin)) break;
 if (o,buf[p=strlen(buf)-1]!='\n') panic("Input line way too long");
 for (p=0;o,isspace(buf[p]);p++) ;
 if (buf[p]=='&#124;' &#124;&#124; !buf[p]) continue; /* bypass comment or blank line */
 last_itm=1;
 break;
}
if (!last_itm) panic("No items");
for (;o,buf[p];) {
 o,namebuf.lr.l=namebuf.lr.r=0;
 for (j=0;j<8 && (o,!isspace(buf[p+j]));j++) { if (buf[p+j]==':' &#124;&#124; buf[p+j]=='&#124;') panic("Illegal character in item name"); o,namebuf.str[j]=buf[p+j]; } if (j==8 && !isspace(buf[p+j])) panic("Item name too long"); oo,lname(last_itm<<2)=namebuf.lr.l,rname(last_itm<<2)=namebuf.lr.r; @<check for duplicate item name@>;
 last_itm++;
 if (last_itm>max_cols) panic("Too many items");
 for (p+=j+1;o,isspace(buf[p]);p++) ;
 if (buf[p]=='&#124;') {
 if (second!=max_cols) panic("Item name line contains &#124; twice");
 second=last_itm;
 for (p++;o,isspace(buf[p]);p++) ;
 }
}
@ @<check for duplicate item name@>=
for (k=last_itm-1;k;k--) {
 if (o,lname(k<<2)!=namebuf.lr.l) continue; if (rname(k<<2)==namebuf.lr.r) break; } if (k) panic("Duplicate item name"); @ I'm putting the option number into the &#124;spr&#124; field of the spacer that follows it, as a possible debugging aid. But the program doesn't currently use that information. @<input the options@>=
while (1) {
 if (!fgets(buf,bufsize,stdin)) break;
 if (o,buf[p=strlen(buf)-1]!='\n') panic("Option line too long");
 for (p=0;o,isspace(buf[p]);p++) ;
 if (buf[p]=='&#124;' &#124;&#124; !buf[p]) continue; /* bypass comment or blank line */
 i=last_node; /* remember the spacer at the left of this option */
 for (pp=0;buf[p];) {
 o,namebuf.lr.l=namebuf.lr.r=0;
 for (j=0;j<8 && (o,!isspace(buf[p+j])) && buf[p+j]!=':';j++) o,namebuf.str[j]=buf[p+j]; if (!j) panic("Empty item name"); if (j==8 && !isspace(buf[p+j]) && buf[p+j]!=':') panic("Item name too long"); @<create a node for the item named in &#124;buf[p]&#124;@>;
 if (buf[p+j]!=':') o,nd[last_node].clr=0;
 else if (k>=second) {
 if ((o,isspace(buf[p+j+1])) &#124;&#124; (o,!isspace(buf[p+j+2])))
 panic("Color must be a single character");
 o,nd[last_node].clr=(unsigned char)buf[p+j+1];
 p+=2;
 }@+else panic("Primary item must be uncolored");
 for (p+=j+1;o,isspace(buf[p]);p++) ;
 }
 if (!pp) {
 if (vbose&show_warnings)
 fprintf(stderr,"Option ignored (no primary items): "O"s",buf);
 while (last_node>i) {
 @<remove &#124;last_node&#124; from its item list@>;
 last_node--;
 }
 }@+else {
 o,nd[i].loc=last_node-i; /* complete the previous spacer */
 last_node++; /* create the next spacer */
 if (last_node==max_nodes) panic("Too many nodes");
 options++;
 o,nd[last_node].itm=i+1-last_node;
 nd[last_node].spr=options; /* option number, for debugging only */
 }
}
@<initialize &#124;item&#124;@>;
@<expand &#124;set&#124;@>;
@<adjust &#124;nd&#124;@>;
@ We temporarily use &#124;pos&#124; to recognize duplicate items in an option.
@<create a node for the item named in &#124;buf[p]&#124;@>=
for (k=(last_itm-1)<<2;k;k-=4) { if (o,lname(k)!=namebuf.lr.l) continue; if (rname(k)==namebuf.lr.r) break; } if (!k) panic("Unknown item name"); if (o,pos(k)>i) panic("Duplicate item name in this option");
last_node++;
if (last_node==max_nodes) panic("Too many nodes");
o,t=size(k); /* how many previous options have used this item? */
o,nd[last_node].itm=k>>2,nd[last_node].loc=t;
if ((k>>2)<second) pp=1; o,size(k)=t+1, pos(k)=last_node; @ @<remove &#124;last_node&#124; from its item list@>=
o,k=nd[last_node].itm<<2; oo,size(k)--,pos(k)=i-1; @ @<initialize &#124;item&#124;@>=
active=itemlength=last_itm-1;
for (k=0,j=primextra;k<itemlength;k++) oo,item[k]=j,j+=(k+2<second? primextra:secondextra)+size((k+1)<<2); setlength=j-4; /* a decent upper bound */ if (second==max_cols) osecond=active,second=j; else osecond=second-1; @ Going from high to low, we now move the item names and sizes to their final positions (leaving room for the pointers into &#124;nb&#124;). @<expand &#124;set&#124;@>=
for (;k;k--) {
 o,j=item[k-1];
 if (k==second) second=j; /* &#124;second&#124; is now an index into &#124;set&#124; */
 oo,size(j)=size(k<<2); if (size(j)==0 && k<=osecond) baditem=k; o,pos(j)=k-1; oo,rname(j)=rname(k<<2),lname(j)=lname(k<<2); if (k<=osecond) o,wt(j)=w0; } @ @<adjust &#124;nd&#124;@>=
for (k=1;k<last_node;k++) { if (o,nd[k].itm<0) continue; /* skip over a spacer */ o,j=item[nd[k].itm-1]; i=j+nd[k].loc; /* no mem charged because we just read &#124;nd[k].itm&#124; */ o,nd[k].itm=j,nd[k].loc=i; o,set[i].i=k; } @ @<report an uncoverable item@>=
{
 if (vbose&show_choices) {
 fprintf(stderr,"Item");
 print_item_name(item[baditem-1],stderr);
 fprintf(stderr," has no options!\n");
 }
}
@ The ``number of entries'' includes spacers (because {\mc DLX2}
includes spacers in its reports). If you want to know the
sum of the option lengths, just subtract the number of options.
@<report the successful completion of the input phase@>=
fprintf(stderr,
 "("O"lld options, "O"d+"O"d items, "O"d entries successfully read)\n",
 options,osecond,itemlength-osecond,last_node);
@ The item lengths after input are shown (on request).
But there's little use trying to show them after the process is done,
since they are restored somewhat blindly.
(Failures of the linked-list implementation in {\mc DLX2} could sometimes be
detected by showing the final lengths; but that reasoning no longer applies.)
@<report the item totals@>=
{
 fprintf(stderr,"Item totals:");
 for (k=0;k<itemlength;k++) { if (k==second) fprintf(stderr," &#124;"); fprintf(stderr," "O"d",size(item[k])); } fprintf(stderr,"\n"); } @ @<randomize the &#124;item&#124; list@>=
for (k=active;k>1;) {
 mems+=4,j=gb_unif_rand(k);
 k--;
 oo,oo,t=item[j],item[j]=item[k],item[k]=t;
 oo,pos(t)=k,pos(item[j])=j;
}
@*Binary branching versus $d$-way branching.
Nodes of the search tree in the previous program {\mc SSXCC}, on which
this one is based, are characterized by the name of a primary item~$i$
that hasn't yet been covered. If that item currently appears in $d$~options
$\{o_1,\ldots,o_d\},ドル node~$i$ has $d$ children, one for each choice of
the option that will cover~$i$.
The present program, however, makes 2-way branches, and its nodes
are labeled with both an item~$i$ and an option~$o$. The left child of
node $(i,o)$ represents the subproblem in which $i$ is covered by~$o,ドル
as before. But the right child represents the subproblem for which
option~$o$ is removed but item~$i$ is still uncovered (unless $d=1,ドル
in which case there's no right child). Thus our search tree is now rather
like the binary tree that represents a general tree. (See {\sl The
Art of Computer Programming}, Section 2.3.2.)
There usually is no good reason to do binary branching when we choose~$i$
so as to minimize~$d$. On the right branch, $i$ will have $d-1$ remaining
options; and no item~$i'$ will have fewer than $d-1$.
But this program is intended to provide the basis for {\it other\/}
programs, which extend the branching heuristic by taking dynamic
characteristics of the solution process into account.
While exploring the left branch in such extensions, we might discover
that a certain item~$i'$ is difficult to cover; hence we might prefer to
branch on an option $o'$ that covers~$i',ドル after rejecting $o$ for item~$i$.
@ We shall say that we're in stage $s$ when we've taken $s$ left branches.
We'll also say, as usual, that we're at level~$l$ when we've taken
$l$ branches altogether.
Suppose, for instance, that we're at level 5, having
rejected $o_1$ for~$i_1,ドル 
accepted $o_2$ for~$i_2,ドル 
accepted $o_3$ for~$i_3,ドル 
rejected $o_4$ for~$i_4,ドル and
rejected $o_5$ for~$i_5$. Then we will have &#124;stage=2&#124;, and
$&#124;choice[k]&#124;=o_k$ for 0ドル\le k<5$; here each $o_k$ is a node whose &#124;itm&#124; field is~$i_k$. Also $$\eqalign{ &#124;stagelevel&#124;[0]&=0,\cr &#124;stagelevel&#124;[1]&=0,\cr &#124;stagelevel&#124;[2]&=1,\cr &#124;stagelevel&#124;[3]&=2,\cr &#124;stagelevel&#124;[4]&=2,\cr &#124;stagelevel&#124;[5]&=2;\cr} \qquad\eqalign{ &#124;levelstage&#124;[0]&=1,\cr &#124;levelstage&#124;[1]&=2,\cr &#124;levelstage&#124;[2]&=5.\cr}$$ The option &#124;choice[k]&#124; has been accepted if and only if &#124;levelstage[stagelevel[k]]=k&#124;. @<glob...@>=
int stage; /* number of choices in current partial solution */
int level; /* current depth in the search tree (which is binary) */
int choice[max_level]; /* the option and item chosen on each level */
int deg[max_level]; /* the number of options the item had at that time */
int levelstage[max_stage]; /* the most recent level at each stage */
int stagelevel[max_level]; /* the stage that corresponds to each level */
ullng profile[max_stage]; /* number of search tree nodes on each stage */
@*The dancing.
Our strategy for generating all exact covers will be to repeatedly
choose an item that appears to be hardest to cover, namely an item whose set
is currently smallest, among all items that still need to be covered.
And we explore all possibilities via depth-first search.
The neat part of this algorithm is the way the sets are maintained.
Depth-first search means last-in-first-out maintenance of data structures;
and the sparse-set representations make it particularly easy to undo
what we've done at deeper levels.
The basic operation is ``including an option.'' That means (i)~removing
from the current subproblem all of the other options with which it conflicts,
and (ii)~considering all of its primary items to be covered, by
making them inactive.
@<solve the problem@>=
{
 level=stage=0;
forward: nodes++;
 if (vbose&show_profile) profile[stage]++;
 if (sanity_checking) sanity();
 @<maybe do a forced move@>;
 @<do special things if enough &#124;mems&#124; have accumulated@>;
 @<set &#124;best_itm&#124; to the best item for branching and &#124;t&#124; to its size@>;
 if (forced) {
 o,best_itm=force[--forced];
 @<do a forced move and &#124;goto advance&#124;@>;
 }
 if (t==inf_size) @<visit a solution and &#124;goto backup&#124;@>;
 @<save the currently active items and their sizes@>;
advance: oo,choice[level]=cur_choice=set[best_itm].i;
 o,deg[level]=t;
 if (!include_option(cur_choice)) goto tryagain;
 @<increase &#124;stage&#124;@>;@+@<increase &#124;level&#124;@>;
 goto forward;
tryagain:@+if (t==1) goto prebackup;
 if (vbose&show_choices)
 fprintf(stderr,"Backtracking in stage "O"d\n",stage);
 goto purgeit;
prebackup: o,saveptr=saved[stage];
backup:@+if (--stage<0) goto done; if (vbose&show_choices) fprintf(stderr,"Backtracking to stage "O"d\n",stage); o,level=levelstage[stage]; purgeit:@+if (o,deg[level]==1) goto prebackup; @<restore the currently active items and their sizes@>;
 o,cur_choice=choice[level];
 @<remove the option &#124;cur_choice&#124;@>;
 @<increase &#124;level&#124;@>;
 goto forward;
}
@ We save the sizes of active items on &#124;savestack&#124;, whose entries
have two fields &#124;l&#124; and &#124;r&#124;, for an item and its size. This stack
makes it easy to undo all deletions, by simply restoring the former sizes.
@<glob...@>=
int level; /* number of choices in current partial solution */
int choice[max_level]; /* the node chosen on each level */
int saved[max_level+1]; /* size of &#124;savestack&#124; on each level */
twoints savestack[savesize];
int saveptr; /* current size of &#124;savestack&#124; */
int tough_itm; /* item whose set of options has just become empty */
@ @<do special things if enough &#124;mems&#124; have accumulated@>=
if (delta && (mems>=thresh)) {
 thresh+=delta;
 if (vbose&show_full_state) print_state();
 else print_progress();
}
if (mems>=timeout) {
 fprintf(stderr,"TIMEOUT!\n");@+goto done;
}
@ @<increase &#124;stage&#124;@>=
if (++stage>maxs) {
 if (stage>=max_stage) {
 fprintf(stderr,"Too many stages!\n");
 exit(-40);
 }
 maxs=stage;
}
@ @<increase &#124;level&#124;@>=
if (++level>maxl) {
 if (level>=max_level) {
 fprintf(stderr,"Too many levels!\n");
 exit(-4);
 }
 maxl=level;
}
oo,stagelevel[level]=stage,levelstage[stage]=level;
@ The &#124;include_option&#124; routine extends the current partial solution,
by using option &#124;opt&#124; to cover one or more of the presently uncovered
primary items. It returns~0, however, if that would make some other
primary item uncoverable. (In the latter case, &#124;tough_itm&#124; is set
to the item that was problematic.)
@<sub...@>=
int include_option(int opt) {
 register int c,optp,nn,nnp,ss,ii,iii,p,pp,s;
 subroutine_overhead;
 if (vbose&show_choices) {
 fprintf(stderr,"S"O"d:",stage);
 print_option(opt,stderr,1);
 }
 for (;o,nd[opt-1].itm>0;opt--) ; /* move to the beginning of the option */
 for (;o,(ii=nd[opt].itm)>0;opt++) {
 pp=nd[opt].loc; /* where &#124;opt&#124; appears in &#124;ii&#124;'s set */
 o,p=pos(ii); /* where &#124;ii&#124; appears in &#124;item&#124; */
 if (p<active) @<deactivate item &#124;ii&#124;, or return 0@>;
 }
 return 1;
}
@ We don't need to remove options from the set of &#124;ii&#124;, because &#124;ii&#124; will
soon be inactive. But of course we do need to remove the options that
conflict with &#124;opt&#124; from the sets of their items.
@<deactivate item &#124;ii&#124;, or return 0@>=
{
 o,ss=size(ii);
 if (ii<second) c=0; else o,c=nd[opt].clr; for (s=ii+ss-1;s>=ii;s--) if (s!=pp) {
 o,optp=set[s].i;
 if (c==0 &#124;&#124; (o,nd[optp].clr!=c))
 @<remove &#124;optp&#124; from its other sets, or return 0@>;
 }
 o,iii=item[--active];
 oo,item[active]=ii,item[p]=iii;
 oo,pos(ii)=active,pos(iii)=p;
}
@ At this point &#124;optp&#124; points to a node of an option that we want to
remove from the current subproblem. We swap it out of the sets of
all its items except for &#124;nd[optp].itm&#124; itself, and except for
the sets of inactive secondary items. (The latter have been purified,
and we shouldn't mess with their sets.)
@<remove &#124;optp&#124; from its other sets, or return 0@>=
{
 register int nn,ii,p,ss,nnp;
 for (nn=optp;o,nd[nn-1].itm>0;nn--) ; /* move to beginning of the option */
 for (;o,(ii=nd[nn].itm)>0;nn++) if (nn!=optp) {
 p=nd[nn].loc;
 if (p>=second && (o,pos(ii)>=active)) continue; /* &#124;ii&#124; already purified */
 o,ss=size(ii)-1;
 if (ss<=1 && p<second) { if (ss==0) { if ((vbose&show_details) && level<show_choices_max && level>=maxl-show_choices_gap) {
 fprintf(stderr," can't cover");
 print_item_name(ii,stderr);
 fprintf(stderr,"\n");
 }
 tough_itm=ii;
 forced=0;
 return 0; /* abort the deletion, lest &#124;ii&#124; be wiped out */
 }
 else o,force[forced++]=ii;
 }
 o,nnp=set[ii+ss].i;
 o,size(ii)=ss;
 oo,set[ii+ss].i=nn,set[p].i=nnp;
 oo,nd[nn].loc=ii+ss,nd[nnp].loc=p;
 updates++;
 }
}
@ At this point every active primary item has at least two options in its set.
Therefore, when we delete &#124;cur_choice&#124; from the sets of each of its
active items, every set will still be nonempty.
@<remove the option &#124;cur_choice&#124;@>=
{
 register int ii,ss,p,nnp;
 for (;o,nd[cur_choice-1].itm>0;cur_choice--) ; /* move to beginning */
 for (;o,(ii=nd[cur_choice].itm)>0;cur_choice++) {
 p=nd[cur_choice].loc;
 if (p>=second && (o,pos(ii)>=active)) continue; /* &#124;ii&#124; inactive */ 
 o,ss=size(ii)-1;
 oo,nnp=set[ii+ss].i,size(ii)=ss;
 oo,set[ii+ss].i=cur_choice,set[p].i=nnp;
 oo,nd[cur_choice].loc=ii+ss,nd[nnp].loc=p;
 updates++;
 }
}
@ If a weight becomes dangerously large, we rescale all the weights.
(That will happen only when &#124;dwfactor&#124; isn't 1.0. Adding a constant
eventually ``converges'': For example, if the constant is 1, we have convergence
to 2ドル^{17}$ after 2ドル^{17}-1=16777215$ steps.
If the constant~&#124;dw&#124; is .250001, convergence
to \.{8.38861e+06} occurs after 25165819 steps!)
(Note: I threw in the parameters &#124;dw&#124; and &#124;dwfactor&#124; only to do experiments.
My preliminary experiments didn't turn up any noteworthy results.
But I didn't have time to do a careful study; hence there might
be some settings that work unexpectedly well. The code for rescaling
might be flaky, since it hasn't been tested very thoroughly at all.)
@d dangerous 1e32f
@d wmin 1e-30f
@<increase the weight of &#124;tough_itm&#124;@>=
cmems+=2,oo,wt(tough_itm)+=dw;
if (vbose&show_record_weights && wt(tough_itm)>maxwt) {
 maxwt=wt(tough_itm);
 fprintf(stderr,""O"8.1f ",maxwt);
 print_item_name(tough_itm,stderr);
 fprintf(stderr," "O"lld\n",nodes);
}
if (vbose&show_weight_bumps) {
 print_item_name(tough_itm,stderr);
 fprintf(stderr," wt "O".1f\n",wt(tough_itm));
}
dw*=dwfactor;
if (wt(tough_itm)>=dangerous) {
 register int k;
 register float t;
 tmems=mems;
 for (k=0;k<itemlength;k++) if (o,item[k]<second) { o,t=wt(item[k])*1e-20f; o,wt(item[k])=(t<wmin?wmin:t); } dw*=1e-20f; if (dw<wmin) dw=wmin; w0*=1e-20f; if (w0<wmin) w0=wmin; cmems+=mems-tmems; } @ @<maybe do a forced move@>=
while (forced) {
 o,best_itm=force[--forced];
 if (o,pos(best_itm)<active) { @<do a forced move and &#124;goto advance&#124;@>;
 }
}
@ @<sub...@>=
void print_weights(void) {
 register int k;
 for (k=0;k<itemlength;k++) if (item[k]<second && wt(item[k])!=w0) { print_item_name(item[k],stderr); fprintf(stderr," wt "O".1f\n",wt(item[k])); } } @ The ``best item'' is considered to be an active primary item that minimizes the number of remaining choices. If there are several candidates, we choose the leftmost. (This program explores the search space in a different order from {\mc DLX2}, because the ordering of items in the active list is no longer fixed. Thus ties are broken in a different way.) We assume that &#124;t&#124; is set to &#124;inf_size&#124; if and only if all primary items have been covered. We also assume that &#124;t&#124; is set to~1 if and only if some uncovered primary item has size~1. (Every uncovered primary item must have size at least~1, because we've been careful to avoid any choices that could cause a size to become~0.) Notice that a secondary item is active if and only if it has not been purified (that is, if and only if it hasn't yet appeared in a chosen option). Important: The code below will usually be changed, via a change file, so that the best item is chosen by using another heuristic. Whatever heuristic is used, it {\it must\/} deliver a primary item whose option size~$s$ is 1, if such an item exists. In other words, it must somehow recognize a forced move, unless there are no forced moves. @d inf_size 0x7fffffff @<set &#124;best_itm&#124; to the best item for branching...@>=
{
 t=inf_size,tmems=mems;
 if ((vbose&show_details) &&
 level<show_choices_max && level>=maxl-show_choices_gap)
 fprintf(stderr,"Level "O"d:",level);
 for (k=0;k<active;k++) if (o,item[k]<second) { o,s=size(item[k]); if ((vbose&show_details) && level<show_choices_max && level>=maxl-show_choices_gap) {
 print_item_name(item[k],stderr);
 fprintf(stderr,"("O"d)",s);
 }
 if (s<=1) { if (s==0) fprintf(stderr,"I'm confused.\n"); /* &#124;include_option&#124; missed this */ else o,force[forced++]=item[k]; }@+else if (s<=t) { if (s<t) best_itm=item[k],t=s; else if (item[k]<best_itm) best_itm=item[k]; /* suggested by P. Weigel */ } } if ((vbose&show_details) && level<show_choices_max && level>=maxl-show_choices_gap) {
 if (forced) fprintf(stderr," found "O"d forced\n",forced);
 else if (t==inf_size) fprintf(stderr," solution\n");
 else {
 fprintf(stderr," branching on");
 print_item_name(best_itm,stderr);
 fprintf(stderr,"("O"d)\n",t);
 }
 }
 if (t>maxdeg && t<inf_size && !forced) maxdeg=t; if (shape_file) { if (t==inf_size) fprintf(shape_file,"sol\n"); else { fprintf(shape_file,""O"d",t); print_item_name(best_itm,shape_file); fprintf(shape_file,"\n"); } fflush(shape_file); } cmems+=mems-tmems; } @ @<visit a solution and &#124;goto backup&#124;@>=
{
 count++;
 if (spacing && (count mod spacing==0)) {
 printf(""O"lld:\n",count);
 for (k=0;k<stage;k++) print_option(choice[levelstage[k]],stdout,0); fflush(stdout); } if (count>=maxcount) goto done;
 goto backup;
}
@ @<save the currently active items and their sizes@>=
o,saved[stage]=saveptr;
if (saveptr+active>maxsaveptr) {
 if (saveptr+active>=savesize) {
 fprintf(stderr,"Stack overflow (savesize="O"d)!\n",savesize);
 exit(-5);
 }
 maxsaveptr=saveptr+active;
}
for (p=0;p<active;p++) ooo,savestack[saveptr+p].l=item[p],savestack[saveptr+p].r=size(item[p]); saveptr+=active; @ @<restore the currently active items and their sizes@>=
o,active=saveptr-saved[stage];
saveptr=saved[stage];
for (p=0;p<active;p++) oo,size(savestack[saveptr+p].l)=savestack[saveptr+p].r; @ A forced move occurs when &#124;best_itm&#124; has only one remaining option. In this case we can streamline the computation, because there's no need to save the current active sizes. (They won't be looked at.) @<do a forced move and &#124;goto advance&#124;@>=
{
 if ((vbose&show_choices) && level<show_choices_max) fprintf(stderr,"(forcing)\n"); o,saved[stage]=saveptr; /* nothing placed on &#124;savestack&#124; */ t=1; goto advance; } @ @<sub...@>=
void print_savestack(int start,int stop) {
 register k;
 for (k=start;k<stop;k++) { print_item_name(savestack[k].l,stderr); fprintf(stderr,"("O"d), "O"d\n",savestack[k].l,savestack[k].r); } } @ @<sub...@>=
void print_state(void) {
 register int l,s;
 fprintf(stderr,"Current state (level "O"d, stage "O"d):\n",level,stage);
 for (l=0;l<level;l++) { if (levelstage[stagelevel[l]]!=l) fprintf(stderr,"~"); print_option(choice[l],stderr,-1); fprintf(stderr," (of "O"d)\n",deg[l]); if (l>=show_levels_max) {
 fprintf(stderr," ...\n");
 break;
 }
 }
 fprintf(stderr," "O"lld solutions, "O"lld mems, and max level "O"d so far.\n",
 count,mems,maxl);
}
@ During a long run, it's helpful to have some way to measure progress.
The following routine prints a string that indicates roughly where we
are in the search tree. The string consists of node degrees,
preceded by `\.{\char`\~}' if the node wasn't the current node in
its stage (that is, if the node represents an option that has already
been fully explored --- ``we've been there done that'').
Following that string, a fractional estimate of total progress is computed,
based on the na{\"\i}ve assumption that the search tree has a uniform
branching structure. If the tree consists
of a single node, this estimate is~.5. Otherwise, if the first choice
is the $k$th choice in stage~0 and has degree~$d,ドル
the estimate is $(k-1)/(d+k-1)$ plus 1ドル/(d+k-1)$ times the
recursively evaluated estimate for the $k$th subtree. (This estimate
might obviously be very misleading, in some cases, but at least it
tends to grow monotonically.)
Fine point: If we've just backtracked within stage &#124;stage&#124;,
the string of node degrees with end with a `\.{\char`\~}' entry,
and we haven't yet made {\it any\/} choice in the current~stage.
The test `&#124;l==level-1&#124;' below uses the fact that &#124;levelstage[stage]=level&#124;
to adjust the fractional estimate appropriately for the partial
progress in the current stage.
@<sub...@>=
void print_progress(void) {
 register int l,ll,k,d,c,p,ds=0;
 register double f,fd;
 fprintf(stderr," after "O"lld mems: "O"lld sols,",mems,count);
 for (f=0.0,fd=1.0,l=0;l<level;l++) { if (l<show_levels_max) fprintf(stderr," "O"s"O"d",levelstage[stagelevel[l]]==l?"":"~",deg[l]); if (levelstage[stagelevel[l]]==l &#124;&#124; l==level-1) { /* see remark above */ for (k=1,d=deg[l],ll=l-1; ll>=0 && stagelevel[ll]==stagelevel[l];k++,d++,ll--) ;
 fd*=d,f+=(k-1)/fd; /* choice &#124;l&#124; is treated like &#124;k&#124; of &#124;d&#124; */
 }
 if (l>=show_levels_max && !ds) ds=1,fprintf(stderr,"...");
 }
 fprintf(stderr," "O".5f\n",f+0.5/fd);
}
@ @<print the profile@>=
{
 fprintf(stderr,"Profile:\n");
 for (k=0;k<=maxs;k++)
 fprintf(stderr,""O"3d: "O"lld\n",
 k,profile[k]);
}
@*Index.
</div><div class="naked_ctrl">
<form action="/index.cgi/speech" method="get" name="gate">
<p><a href="http://altstyle.alfasado.net">AltStyle</a> によって変換されたページ <a href="https://cs.stanford.edu/~knuth/programs/ssxcc-binary.w">(-&gt;オリジナル)</a>
/ <label>アドレス: <input type="text" name="naked_post_url" value="https://cs.stanford.edu/~knuth/programs/ssxcc-binary.w" size="22" /></label> <label>モード: <select name="naked_post_mode">
<option value="default">デフォルト</option>
<option value="speech" selected="selected">音声ブラウザ</option>
<option value="ruby">ルビ付き</option>
<option value="contrast">配色反転</option>
<option value="larger-text">文字拡大</option>
<option value="mobile">モバイル</option>
</select>
<input type="submit" value="表示" />
</p>
</form>
</div>