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convert/base converts the base-10 integer n to base-$\mathrm{\beta }$ or converts the list of integers L from base-$\mathrm{\alpha }$ to base-$\mathrm{\beta }$, in which case we interpret L as the number $\sum _{k=1}^{\mathrm{nops}\left(L\right)}{L}_k{\mathrm{\alpha }}^{k-1}$. It is assumed that $0\le L_k<\mathrm{\alpha }$.

The result is a list of the base-$\mathrm{\beta }$ digits of the converted input.

$\mathrm{convert}\left(32\&comma;\mathrm{base}\&comma;16\right)$

$\left[0\&comma;2\right]$

$\mathrm{convert}\left(17\&comma;\mathrm{base}\&comma;3\right)$

$\left[2\&comma;2\&comma;1\right]$

$\mathrm{convert}\left(\left[2\&comma;2\&comma;1\right]\&comma;\mathrm{base}\&comma;3\&comma;10\right)$

$\left[7\&comma;1\right]$

$\mathrm{convert}\left(\left[0\&comma;0\&comma;0\&comma;1\right]\&comma;\mathrm{base}\&comma;2\&comma;8\right)$

$\left[0\&comma;1\right]$

$\mathrm{convert}\left(\left[0\&comma;1\right]\&comma;\mathrm{base}\&comma;8\&comma;16\right)$

$\left[8\right]$

$\mathrm{convert}\left(\left[0\&comma;2\right]\&comma;\mathrm{base}\&comma;16\&comma;2\right)$

$\left[0\&comma;0\&comma;0\&comma;0\&comma;0\&comma;1\right]$

$\mathrm{convert}\left(\left[0\&comma;2\right]\&comma;\mathrm{base}\&comma;16\&comma;32\right)$

$\left[0\&comma;1\right]$