[Jprogramming] substring matching between two arrays

Tue Nov 13 00:41:52 UTC 2018

I think I fell into the trap of thinking of / only in its monadic form.
Here's a version that seems to click with me:
I."1 |: (shortNames) +/@(E. every)/ (fullNames)
It uses / and takes advantage of every to mask the complexity of
boxing/unboxing (at least to me). I often reach for each/every
On Mon, Nov 12, 2018 at 7:14 PM Henry Rich <henryhrich at gmail.com> wrote:
> / IS rank alone.
>> x u/ y is defined as
>> x u"(lu,_) y
>> where lu is the left rank of u. Apply each CELL of x to the ENTIRE y.
>> Henry Rich
>>> On 11/12/2018 7:00 PM, Joe Bogner wrote:
> > Thanks all. The solutions above were more complicated than I expected. I
> > had assumed I was missing something obvious. The obvious miss was to use
> /
> > ... I was thinking I could do something with rank alone
> >
> > For comparison it is combination of map and reduce in javascript
> >
> > ['Joe B','Joe Q','Bobby Z','Janet F'].map(function(x) { return
> > ['Joe','Bob','Jane'].reduce(function(acc,y,idx) { return
> > x.indexOf(y)>=0?idx:acc },-1) })
> >
> > [0, 0, 1, 2]
> >
> >
> >
> > On Mon, Nov 12, 2018 at 6:17 PM 'Mike Day' via Programming <
> > programming at jsoftware.com> wrote:
> >
> >> or this variant?
> >>
> >> f(1 i.~"1+./@E.~&> /)s. NB. f & s obvious?
> >> 0 0 1 2
> >>
> >> This lists the index of the first instance of a substring of each
> element
> >> of fullNames in the
> >> shortNames boxed list. It assumes it's there somewhere, but you can use
> >> the property
> >> that non-inclusion is shown by index = length or number of shortNames.
> >>
> >> Any help,
> >>
> >> Mike
> >>
> >>
> >>> On 12 Nov 2018, at 22:29, Brian Schott <schott.brian at gmail.com> wrote:
> >>>
> >>> Is this anything you can use?
> >>>
> >>> I.fullNames(((]))&: >"0/-:"1 ((#@]{.[))& >"0/) shortNames
> >>>
> >>>
> >>> --
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> >>> Brian Schott
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