Why does #{nil, "sun"} output 2, whereas a={}; a[2]="sun"; print(#a) output 0?
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- Subject: Why does #{nil, "sun"} output 2, whereas a={}; a[2]="sun"; print(#a) output 0?
- From: 孙世龙 sunshilong <sunshilong369@...>
- Date: 2020年10月12日 14:38:34 +0800
Hi, list
Here are the first code snippet and the output:
>a={nil, "sun"} --output: 2
Here are the second code snippet and the output:
>b = {}
>b[2] = "sun"
>print(#b) --output:0
Here are the third code snippet and the output:
> function printTab(tab)
>> for k,v in pairs(tab) do
>> print(k,v)
>> end
>> end
>
>type(a) == type(b) --output:true
>a == b --output: false amazing!!!
>> printTab(a) --output: 2 sun
>> printTab(b) --output: 2 sun
It's amazing that "printTab(a)" and "printTab(b)" are the same whereas
"#a" and "#b" are different (and "a == b" outputs false).
Could somebody shed some light on this question?
Best regards
Sunshilong