Re: how to translate lua pattern "(.*)and(.*)" with lpeg re ?
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- Subject: Re: how to translate lua pattern "(.*)and(.*)" with lpeg re ?
- From: albertmcchan <albertmcchan@...>
- Date: 2018年1月25日 09:33:01 -0500
this version "remove" all a's, and match only 'nd':
pat = re.compile ([[
line <- match_and+ -> drop3 {.*}
match_and <- remove_a match_nd
remove_a <- [^a]* . 'a'*
match_nd <- 'nd' / . match_and
]], { drop3 = function(s) return string.sub(s, 1, -4) end }
)
I tried building the same re pattern without recursive grammar, but failed.