Correct way to write C/Lua mixed module
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- Subject: Correct way to write C/Lua mixed module
- From: andre@...
- Date: 2012年10月02日 16:52:57 +0000
Hi All,
I'm writing a module which has mixed native C functions and Lua code. My goal is to have it available by only requiring it. My DLL exports only one function:
------------------------------8<------------------------------
extern "C"
{
LUAMOD_API int luaopen_task( lua_State* L )
{
static const luaL_Reg statics[] =
{
{ "getCurrentTimeMillis", module_getCurrentTimeMillis },
{ NULL, NULL }
};
// Register C functions.
luaL_newlib( L, statics ); // table
// Register Lua functions.
if ( luaL_loadstring( L, s_LuaCode ) != LUA_OK ) // table function
{
fprintf( stderr, "%s\n", lua_tostring( L, -1 ) );
return 0;
}
if ( lua_pcall( L, 0, 1, 0 ) != LUA_OK ) // table function
{
fprintf( stderr, "%s\n", lua_tostring( L, -1 ) );
return 0;
}
lua_pushvalue( L, -2 ); // table function table@1
if ( lua_pcall( L, 1, 0, 0 ) != LUA_OK ) // table
{
fprintf( stderr, "%s\n", lua_tostring( L, -1 ) );
return 0;
}
return 1;
}
}
------------------------------8<------------------------------
s_LuaCode is a C array generated with the following source code
------------------------------8<------------------------------
local function doSomething()
-- ...
end
return function( module )
module.doSomething = doSomething
end
------------------------------8<------------------------------
The Lua code returns a function which receives a table where the module functions are to be registered, and this function is called as part of luaopen_task.
Questions:
1. Is there a better way to handle a C/Lua mixed module? I don't need anything fancy, just register Lua and C functions.
2. Can/should I call lua_error in luaopen_task if one of the functions I call fails?
Thanks in advance,
Andre