RE: string.gsub pattern question
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- Subject: RE: string.gsub pattern question
- From: Thomas Buergel <Thomas.Buergel@...>
- Date: 2011年9月27日 10:40:55 +0000
> I don't believe this can be done with a simple pattern replacement.
> You have to move into using a custom callback function to do the
> negative look-behind, something like:
Or simpler, do a two-step replacement:
1. "<br>\n" -> "\n"
2. "\n" -> "<br>\n"
strOutput = strInput:gsub("<br>\n", "\n"):gsub("\n", "<br>\n")
This doesn't cover cases where you have trailing whitespace (before \n), though. If the input is hand-written, you might want to eat all the trailing whitespace, too:
strOutput = strInput:gsub("<br>%s*\n", "\n"):gsub("%s*\n", "<br>\n")
Test case:
s="asdf<br> \n12 34 \nblablah"
print(s:gsub("<br>%s*\n", "\n"):gsub("%s*\n", "<br>\n"))