Re: 5.2 work3 manual
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- Subject: Re: 5.2 work3 manual
- From: Gavin Wraith <gavin@...>
- Date: 2010年5月19日 15:17:17 +0100
In message <AANLkTikNqtM3VWqR5FqJyNvT5obhe3RYqNjyGLtuGWzS@mail.gmail.com>
you wrote:
> It is not guaranteed to be 0 if t[1] is nil:
>
> > print(#{nil, 1})
> 2
The business of "holes" seems to founder on the fact that "k is not
a defined key of t" is not equivalent to "t[k] has the value nil".
My thinking was that if t[1] is not defined, then the array part of
t is {} - I had believed that # should depend only on the array
part of a table.
Perhaps nil is being overloaded with too many meanings?
--
Gavin Wraith (gavin@wra1th.plus.com)
Home page: http://www.wra1th.plus.com/