Re: comparing binary numbers with strings
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- Subject: Re: comparing binary numbers with strings
- From: Adrien de Croy <adrien@...>
- Date: 2007年10月27日 13:55:27 +1300
how can adding 2 numbers, converting it to a string, then pattern
matching it to "2" do anything useful? string.match returns either a
substring or nil. So, you'll get something non-nil if the result of the
addition contains the digit 2 in decimal. That's certainly not what was
requested?
e.g. take 10000 and 00100, no matching bits but
16 + 4 = 20, which contains "2"
without bit-wise operators in lua (e.g. XOR), you're going to need to go
through the digits one at a time I'm afraid...
Merick wrote:
Shmuel Zeigerman wrote:
Merick wrote:
I was wondering if there was any way - other than using a for loop
to iterate through each character - to use the string library to
compare two strings with representations of binary numbers and tell
whether or not any of the 1's in the strings are in the same position?
Something like compare("11100", "00011") would return false and
compare("11100","00111") would return true
function compare(a,b)
a = tostring(tonumber(a) + tonumber(b))
return a:match"2"
end
Dangit, that's so simple I can't believe I didn't think of it myself!
Thanks
--
Adrien de Croy - WinGate Proxy Server - http://www.wingate.com