RE: Calling a chunk by file name
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- Subject: RE: Calling a chunk by file name
- From: "Virgil Smith" <Virgil@...>
- Date: Thu, 5 Feb 2004 12:03:07 -0600
> Like I said, it is easy to implement different mains,
> but it'll not be easy to do it consistently with the
> 1-file case.
> --lhf
Just my own thoughts...
I think that by definition what is being requested is inconsistent with the
standard 1-file case. I think the most flexible option would be to pass all
of the resulting chunks to one particular lua file (along with the
filenames). Personally, I would pass the resulting chunks in one table and
the names in another (and names could be matched to chunks through
ordering).
Here is an example of such a call
luac -o MyOutput.luac -M MyMain.lua prog1.lua prog2.lua prog3.lua
The effective "default" implementation of such a "main" file could be
(assuming arg[1] is the table of chunks) ....
table.foreachi(arg[1], function (i,f) do f(); return; end)
return
An implementation that destroyed the ordering information, and returned a
table mapping from name to chunk could be....
local RetTable = {}
local Names = arg[2]
table.foreachi(arg[1], function (i, f) do RetTable[Names[i]] = f; return;
end)
return RetTable
And here is a representation of what would (effectively) be in the output
file...
local Funcs = {loadfile("prog1.lua"), loadfile("prog2.lua"),
loadfile("prog3.lua")}
local Names = {"prog1.lua", "prog2.lua", "prog3.lua"}
local Main = loadfile("MyMain.lua")
return Main(Funcs, Names)