Simple case: void foo(T)() { } struct f(alias func=foo!(int)) { } void main() { f!() myf; } Error in 1.036: Error: foo!(int) is not a symbol Error in 2.019: testtemplatealias.d(5): Error: foo!(int) is used as a type testtemplatealias.d(11): template instance f!() does not match template declaration f(alias func = foo!(int)) testtemplatealias.d(11): Error: f!() is used as a type testtemplatealias.d(11): variable testtemplatealias.main.myf voids have no value Workaround is to alias the default parameter before using as the default parameter: alias foo!(int) defaultFoo; struct f(alias func=defaultFoo) { }
Note that in the case where you want the default value to depend on other template parameters, such as: struct f(T, alias func=foo!(T)) This is much tricker. I found that the cleanest way to workaround is to avoid default parameters, and just alias the less specific ones: struct f(T, alias func) { } template f(T) { alias f!(T, foo!(T)) f; }
Fixed dmd 1.038 amd 2.022
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