Write code to complete printFactorial()'s recursive case. Sample output if input is 5: |5! = 5 * 4 * 3 * 2 * 1 =わ 120 11 2 12 13 14 15 10 10 TE 16 17 18 19 20 21 22 23 24 25 22 26 } else if (factCounter == 1) { // Base case: Print 1 and result System.out.println(factCounter + = " + factValue); } else { // Recursive case } System.out.print (factCounter + nextCounter = factCounter - 1; nextValue = nextCounter * factValue; /* Your solution goes here */ public static void main (String [] args) { Scanner scnr = new Scanner(System.in); int userval;

Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a string and remove all occurrences of the word chicken and count how many chickens were removed. Keep in mind that removing a chicken might show a previously hidden chicken. You may find substring and indexOf useful. achickchickenen - removing the 1st chicken would leave achicken behindachicken - removing the 2nd chicken would leave a behindSample Data : itatfunitatchickenfunchchickchickenenickenchickchickfunchickenbouncetheballchickenSample Output : 01302

Write code to complete factorial_str('s recursive case. Sample output with input: 5 5! 5 * 4 * 3 * 2 * 1 = 120 %3D 344614.2214230.qx32qy7 output_string = 2 if fact_counter output_string += '1' elif fact_counter == 1: out put_string += str(fact_counter) + 4 == 0: # Base case: 0! = 1 5. # Base case: print 1 and result 7 + str(fact_value) else: # Recursive case output_string += str(fact_counter) + next counter = next_value output_string += 9 fact_counter next_counter * fact_value 10 - 1 11 ... 12 Your solution goes here 13 14 return output_string 15 int(input ()) '.format (user_val), end="") 16 user val 17 print ('{}! 18 print(factorial_str (user_val, user_val))

Fix the code below so that there is a function that calculate the height of the triangle. package recursion; import javax.swing.*;import java.awt.*; /** * Draw a Sierpinski Triangle of a given order on a JPanel. * * */public class SierpinskiPanel extends JPanel { private static final int WIDTH = 810; private static final int HEIGHT = 830; private int order; /** * Construct a new SierpinskiPanel. */ public SierpinskiPanel(int order) { this.order = order; this.setMinimumSize(new Dimension(WIDTH, HEIGHT)); this.setMaximumSize(new Dimension(WIDTH, HEIGHT)); this.setPreferredSize(new Dimension(WIDTH, HEIGHT)); } public static double height(double size) { double h = (size * Math.sqrt(3)) / 2.0; return h; } /** * Draw an inverted triangle at the specified location on this JPanel. * * @param x the x coordinate of the upper left corner of the triangle * @param y the y...

Write a Non tail recursion and a tail recursion method in Java with a test class that does the following: The factorial of a positive integer n —which we denote as n!—is the product of n and the factorial of n 1. The factorial of 0 is 1. Write two different recursive methods in Java that each return the factorial of n. Please and Thank you

Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16 def raise_to_power(base_val, exponent_val): if exponent_val == 0: result_val = 1 else: result_val = base_val * ''' Your solution goes here ''' return result_val user_base = int(input())user_exponent = int(input()) print('{}^{} = {}'.format(user_base, user_exponent, raise_to_power(user_base, user_exponent)))

Consider the following recursive method: Public static int Fib(int a1, int a2, int n){ if(n == 1) return a1; else if (n == 2) return a2;else return Fib(a1, a2, n-1) + Fib(a1, a2, n-2);} Please draw the recursion trace for Fib(2,3,5)

Given a list of integers, you want to know whether it is possible to divide the integers into two sets, so that the sums of the two sets are the same. Every integer must be in one set or the other. Write a recursive helper method that takes any number of arguments you like, and make the initial call to your recursive helper method from equalSum(). Do not use any loops or regular expressions. Test case 1: equalSum([2, 3, 5]) true Test case 2: equalSum([2, 2, 5]) false

Please explain the questions related to the code below: //1. Why is 20 printed 3 times and why does it start with 1, but end with 2? //2. What is the base case for this recursive method and why? //3. How would you implement this using a loop? //4. What is each if statement checking? //5. Would a solution to this using loops require more or less code and would it be more or less effecient? //6. Why is recursion a good choice to solve this problem? //7. How can recursion become infinite? //8. When is recursion appropriate? /* Load the code below into a cloud compiler and run each method one at a time by removing the comments for the method. Walk through the code as a group and explore how the code works. Submit the answers to the numbered questions for credit. */ public class DemoRecur { //Simple statement designed to show control flow in recursion public static void printDemo(int x, int max) {...

help create a Java recursive method that determines if a number is a prime number

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Write a recursive method to determine whether a String contains a 'q' not immediately followed by a 'u' (ignoring capitalization). In other words: • the word does contain at least one 'q' • and that q is followed by anything except a 'u' Carefully review the provided driver program to see example test cases. The method header is: public static boolean qNotFollowedByU(String word)

A recursive method with no base case? 1.causes an infinite loop 2.generates no output 3.does not start 4.all of the answers