What is the worse case run time for following algorithm? CountDuplicatePairs This algorithm counts the number of duplicate pairs in a sequence. Input: a1, a2....,an, where n is the length of the sequence. Output: count = the number of duplicate pairs. count := 0 For i = 1 to n For j=i+1 to n If (a1 = aj), count := count +1 End-for End-for Return( count) O 0(n3) O O(n) O 0 (1) OO(n2)

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