Using c++ Write a function isPrime that accepts a positive long num and returns true IFF num is prime (e.g. only divisible by 1 and itself).

Do asap please.

write a function EvalNumbers() that has five integer paramaters ( or arguments), and returns the count of arguments where the value is an odd number, positive and mutiple of 3. write a complete C++ program that includes that function and that is called from main() with values obtained from the user

Write a function with one integer parameter that will return the sum of the divisors of its argument c++

In C++, m%n is the remainder when the integer m is divided by the integer n. We can define a function to test whether an integer is even as follows: bool even(int k) { if ( k % 2 == 1 ) return false; else return true;} Translate this function into a standard mathematical function specification.

Answer in C++

Use C++ programming language Write a program , that finds solution (roots) of quadratic equation, allow user to input as much as function they need , terminate program , when user inputted N = No. You need to test if function has two real solution, one real solution or imaginary solution. You must use functions to find roots.

Write a C++ function to find nth term of sequence given below, n is passed as argument to the function and function prints the nth term in output. Sequence: 1,4,9,16,25,........n2

Write a function that displays all the numbers between two integers in n lines, that are divisible by 5 or 7 (not by both). So, the function should take as parameters the minimum and maximum of integer numbers and n. If no values are passed to them, this function should display the numbers between 1 and 100 in 10 lines. Write a test program to test your function. just in C++

2. Modular arithmetic Write a function that returns the result of any integer modulo of n (i.e., reduce theinteger modulo n). Note that the C++ operator % can be used, but it returns a negativevalue, for example, -1 % 3 yields -1, so we need to do something adjustment (recallthat -1 mod 3 = 2 because -1= (-1)×ばつ3+2). Therefore, we will use the mod() functionfrom this step to implement the later encode() and decode() functions. /* precondition: n is greater than 1,a can be negativepostcondition: return a mod n (as defined in class)a mod n = r if and only if a = nk+r, 0 =< r < n (note thatr needs to be non-negative).*/int mod (int a, int n); -Please write in c++