Use a loop to print the alphabet from A to Z. Print all the characters in one line, with no spaces between them. Also use another loop to print the alphabet from z to a. Print all the character in one line, with no spaces between them. Note: There will be two lines in the output. One of the uppercase letters from A to Z, and a second line for the lowercase letter from z to a.

Please help me with this because I need something visual because I don't understand this and the parts as well.

Create a fully documented java applet that produces a Bulls Eye with six concentriccircles using two colors as shown below. You may choose your own color combination.(See pg. 260, Programming Project 13, Savitch).Use Named Constants to establish and maintain the x and y settings for the top leftcorner and the amount to change the diameter for each circle.Use a for loop to control the drawing of each of the 6 circles. Within the loop, determinethe correct graphic settings for the fillOval method by increasing the x, y values to moveinward; reducing the diameter for the new circle and alternating the color setting.hint: to determine color setting  LoopCtr % 2 will alternate between 0 and 1Test your code using the AppletViewer

I am having trouble with coding this in the assignment into python. It is attached as a image

I need help with creating a Java program based with the loop methods:

Prompt for the user to enter their name. Print out their name forwards, backwards, vertically-forwards and vertically-backwards. You will need to declare a String variable, use Scanner to get input of a String, call a String method to isolate one letter and create a loop that traverses the name forwards and backwards. Sample Output: Enter your name: Florene Florene enerolF F l o r e n e e n e r o l F HINTS: Scanner input = new Scanner(System.in); String myName = input.nextLine(); // input is a Scanner object int len = myName.length() // len is the number of characters System.out.println (myName.substring(len-1, len)); // prints last letter I need help with coding the name "Pooja" vertically-forwards and vertically-backwards in java. If you could show me what codes to type in, that would be great. Thank you!

Write a java program called Fibonacci.java that prints the first n numbers of the Fibonacci sequence (starting with 0), where n is an integer entered by the user. Use a for loop. Some of the program has been provided below. More info about Fibonacci can be found here:https://www.mathsisfun.com/numbers/fibonacci-sequence.htmlhttps://www.youtube.com/watch?v=wTlw7fNcO-0 import java.util.Scanner;public class Fibonacci { public static void main(String[] args) { Scanner in = new Scanner(System.in); // Setting up scanner System.out.print("Enter an integer: "); int num = in.nextInt(); in.close(); // Close scanner when done using it long current = 1; long previous = 0; // Add for loop logic here }}

Using javascript Simulate rolling two dice by getting two random integers from 1 to 6.a. Count how many rolls it takes to get doubles. Show each roll of the dice (both dice on the same line).b. Separately, i.e. using a separate loop from part (a), count how many rolls it takes to get values that add up to 7. Show each roll of the dice (both dice on the same line).

in java Jump to level 1 The first and second integers in the input are read into variables previousNum and currentNum, respectively. Write a loop that iterates until currentNum is not equal to 6 plus previousNum. In each iteration: Output currentNum, followed by " is 6 plus ", previousNum, and ". Sequence is increasing arithmetically." End with a newline. Assign previousNum with currentNum. Read the next integer from input and assign currentNum with the integer read. After the loop, output the last integer read followed by " breaks the sequence." and a newline. Click here for example Note: Assume that input has at least two integers. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 import java.util.Scanner; public class Sequencing { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); intcurrentNum; intpreviousNum; previousNum=scnr.nextInt(); currentNum=scnr.nextInt(); System.out.println("Sequence starts at "+previousNum+"."); /* Your code...

Create a card game in which the dealer shuffles the deck and deals 13 cards to the player. The player sorts her hand and says whether it includes the King of Hearts. Repeat 4 times so all the cards are dealt eventually. Internally, the player should return true or false without writing to the console. In response, the dealer should write on the console, "You won!" or "You loose again."

Write a program that will print asterisks in the shape of a diamond. The height of the diamond will depend on the value entered by the user. That value MUST be greater than 0, and it MUST be odd. To make sure that the value is correct, you will validate the value once the user has entered it using a validation loop. Then you will print out a diamond in the pattern demonstrated in the sample execution. Remember that the height will vary based on the user input.

in java String inputWord is read from input. Write a while loop that iterates until inputWord is equal to "Finale". In each iteration of the loop: Read integer clothingNumber from input. If clothingNumber is less than 30, output the value of inputWord, followed by ": low on stock" and a newline. Otherwise, output the value of inputWord, followed by ": well stocked" and a newline. Read string inputWord from input. Click here for example 1 2 3 4 5 6 7 8 9 10 11 12 13 14 import java.util.Scanner; public class PairedDataProcessing { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); StringinputWord; intclothingNumber; inputWord=scnr.next(); /* Your code goes here */ } }

Input a number n and print out n lines of text in the pattern below, shown for example n = 5 * * * * 1 * * * 2 1 * * 3 2 1 * 4 3 2 1 5 4 3 2 1 There is exactly one space between numbe4rs, there is no space at the end of each line, and each line ends with a newline. The first two tests will ignore the whitespace.