The MATLAB function arg supports variable arguments, returns the sum of the number of arguments and all arguments, and has a help function. Write the arg so that the next execution results. >> help arg It supports variable arguments. >> [n,m] = arg(5,6) n = 2 m = 11 >> [n, m] = arg(3,4,5) n = 3 m = 12

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palindromes Write a function palindromes that accepts a sentence as an argument. The function then returns a list of all words in the sentence that are palindromes, that is they are the same forwards and backwards. Guidelines: • punctuation characters .,;!? should be ignored • the palindrome check should not depend on case Sample usage:>>> palindromes ("Hey Anna, would you prefer to ride in a kayak or a racecar?") ['Anna', 'a', 'kayak', 'a', 'racecar']>>> palindromes ("Able was I ere I saw Elba.") ['I', 'ere', 'I']>>> palindromes ("Otto, go see Tacocat at the Civic Center, their guitar solos are Wow!") ['Otto', 'Tacocat', 'Civic', 'solos', 'wow']>>> palindromes ("Otto, go see Tacocat at the Civic Center, their guitar solos are wow!")==['Otto', 'Tacocat', 'Civic', 'solos', 'wow'] True

Problem DNA: Subsequence markingA common task in dealing with DNA sequences is searching for particular substrings within longer DNA sequences. Write a function mark_dna that takes as parameters a DNA sequence to search, and a shorter target sequence to find within the longer sequence. Have this function return a new altered sequence that is the original sequence with all non-overlapping occurrences of the target surrounded with the characters >> and <<. Hints: ●くろまる String slicing is useful for looking at multiple characters at once. ●くろまる Remember that you cannot modify the original string directly, you’ll need to build a copy. Start with an empty string and concatenate onto it as you loop. Constraints: ●くろまる Don't use the built-in replace string method. All other string methods are permitted. >>> mark_dna('atgcgctagcatg', 'gcg') 'at>>gcg<<ctagcatg' >>> mark_dna('atgcgctagcatg', 'gc')...

Python only** define the following function: 1. This function must add a task to a checklist, setting its initial value to False. It will accept two parameters: the checklist object to add to, and the task name to add. In addition to adding the task, it must return the (now modified) checklist object that it was given. There is one issue, however: a task cannot be added to a checklist if the name requested is already being used by another task in that checklist. In that case, this function must print a specific message and must return None Define addTask with 2 parameters Use def to define addTask with 2 parameters Use a return statement Within the definition of addTask with 2 parameters, use return _ in at least one place. Do not use any kind of loop Within the definition of addTask with 2 parameters, do not use any kind of loop.

MULTIPLE FUNCTIONS AND RECURSIVE FUNCTIONS HANDS-ON use #include<stdio.h>

Create a flowchart for this program in c++, #include <iostream>#include <vector> // for vectors#include <algorithm>#include <cmath> // math for function like pow ,sin, log#include <numeric>using std::vector;using namespace std;int main(){ vector <float> x, y;//vector x for x and y for y float x_tmp = -2.5; // initial value of x float my_function(float x); while (x_tmp <= 2.5) // the last value of x { x.push_back(x_tmp); y.push_back(my_function(x_tmp)); // calculate function's value for given x x_tmp += 1;// add step } cout << "my name's khaled , my variant is 21 ," << " my function is y = 0.05 * x^3 + 6sin(3x) + 4 " << endl; cout << "x\t"; for (auto x_tmp1 : x) cout << '\t' << x_tmp1;//printing x values with tops cout << endl; cout << "y\t"; for (auto y_tmp1 : y) cout << '\t' << y_tmp1;//printing y values with tops...

The destination of a function's return value may be represented as a sequence of instructions. When making modifications to the stack, keep in mind that they must not prevent the method from returning to its caller.

c programming Task 3: Complete armstrong_task3.c by implementing armstrong_recursive function. int armstrong_recursive (int arm); It performs same operation as in Task 1, however in a recursive manner. A number to be checked whether it is armstrong or not is given as an input and the function returns the summation of the digits. If the returned value is equal to the given input value then it is an armstrong number.

def find_root4(x, epsilon): ''' IN PYTHON Assume: x, epsilon are floating point numbers and epsilon > 0 Use bisection search to find the following root of x such that If x >=0, return y such that x - epsilon <= y ** 2 <= x + epsilon Else, return y such that x - epsilon <= y ** 7 <= x + epsilon Note: You must use bisection search to implement the function. ''' pass

The code box below defines a variable route as a list of directions to navigate a maze. Each instruction is one of the following four basic commands: higher move one step in the positive y direction • lower. move one step in the negative y direction • left: move one step in the negative x direction • right: move one step in the positive x direction Define a function step that takes two arguments, a location (as a tuple of x and y coordinates) and an instruction (higher, lower, left, right) as a string. Given the provided location, it should return the new location (as a tuple of x and y coordinates) when following the specified instruction. If the instruction is invalid, the old location should be returned. Use the function step to determine the final position when starting from the point (0, -4) and following all instructions in the list route. Assign this final position to the variable final_point.

rografmiming CSC 101 Introduction VB Bau Section21436.02. Sntinn 2022 ta46581 OPRIV NEXTO Workbench Exercise 40443- deadne 04020022 1150 PM WORK AREA toThePowerOf is a function thet accepts two int parameters and returns the value of the first parameter raised to the power of the second. An int variable cubeside has aiready been deciared and initialized. Another int vaciable, cubevolume, has already been declared. Write a statement that calls toThePowerof to compute the value of cubeside raised to the power of 3, and store this value in cubevolume. SUBMIT 1 of 1: Sat Apr 02 2022 23:03:03 GMT-0400 (Eastern Dayilght Time) Type your selution here.

Using C++ Language Write a function call with arguments tensPlace, onesPlace, and userInt. Be sure to pass the first two arguments as pointers. Sample output for the given program: tensPlace = 4, onesPlace = 1 Code: #include <stdio.h> void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){ *tensDigit = (DecVal / 10) % 10; *onesDigit = DecVal % 10;} int main(void) { int tensPlace; int onesPlace; int userInt; scanf("%d", &userInt); /* Your solution goes here */ printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace); return 0;}