Strassen’s algorithm is a non-recursive algorithm. True/False? Strassen’s matrix multiplication algorithm follows a Greedy method. True/False?

Provide an explanation of the recursive binary search's stopping condition and the justification for why stopping conditions are necessary for all recursive algorithms.

Define and justify why stopping conditions are required for all recursive algorithms, such as the recursive binary search, in your own words.

Java: Consider the following algorithm for searching in an unsorted array. If the size of the array is 1, then check if it contains the element to be searched. Otherwise, divide the array into two halves, and recursively search both halves. Which of (a)–(c) is false? The running time of this algorithm is O(N) The actual running time of this algorithm is likely to be better than sequential search. This is an example of a divide‐and‐conquer algorithm all of the above are true none of the above is true

Please show and explain so I can nderstand.

Give an account of the stopping condition for the recursive binary search, and elaborate on why such a condition is required of all recursive algorithms.

Using recursion, segregate an array of integers to have the even integers come before the odd using C++

Please show work to the answer.

With the Binary Search algorithm, the algorithm can be developed by the loop-based form as well as a recursive form. Which of the following is not true? O If the item is not found, the loop version returns when the range bounds reach, but the recursive version finishes when the recursive depth is more than half the initial search range. The search range starts with the whole array, and only the recursive version can work on a subrange passed through arguments. O Both forms of the program divide the search range repeatedly in half. O If the item is found, the loop version returns from the entire method, whereas the recursive version returns from one level of recursion.

Use Binary Search, Recursive (Algorithm 2.1) to search for the integer 120 in the following list (array) of integers. Show the actions (execution) step by step. No code needed. Solution: 12 34 37 45 57 82 99 120 134 1. Compute the middle index from initial low (1) and high (9) indices: mid = Continue... A