static int count=0; static void printOutput(ArrayList arr){ count++; int sum=0; for(int i=0;i arr,int i,int n) { if(n==0){ printOutput(arr); } for(int j = i; j <= n; j++) { arr.add(j); findways (arr, j, n: n - i); arr.remove( index: arr.size() - 1); } } public static void main(String] args)throws IOException { BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int n=Integer.parseInt(br.readLine()); ArrayList arr = new ArrayList<>(); findways(arr, : 1,n); System.out.println("total="+(count-1));

Implement the logarithmBase22 method which, given a long integer number, returns the result of Logz2(number), rounded down to the nearest floor integer. Design and implement this as a recursive method. Read the test cases in the JUnit tester file for more detailed specification.

I need help coding this in java language.

how to write a java program that determine if a string is a palidrome using a recursive method and a non-recursive method (ignore characters that are not letters). Then write a driver to test the two versions of the two methods. (A palindrome is a string that reads the same forward as well as backward. For example, "otto" and "never odd or even" are palindromes) (driver can be hard coded)

Please do it using recursive approch. Recently | asked the same question, but i get in iterative approch. So please take mind on that. Write a java program to find the LCM of two user entered integer numbers.

Give a recursive definition for the set of all strings of a’s and b’s that begins with an a and ends in a b. Say, S = { ab, aab, abb, aaab, aabb, abbb, abab..} Let S be the set of all strings of a’s and b’s that begins with a and ends in a b. The recursive definition is as follows – Base:... Recursion: If u ∈ S, then... Restriction: There are no elements of S other than those obtained from the base and recursion of S.

Do the trace in detail and submit The source Code As Well From the following recursive method Trace (in details) the calling of the above method with any input from your choice such that thereturned value will be 19. public static int think(int x) {if(x<10)if(x%2!=0)return x;elsereturn 0;elseif(x%2!=0)return x%10 + think(x/10);elsereturn think(x/10);}

Write a recursive method, matchingParen (String str), that returns: true if str is a nesting of zero or more pairs of parentheses, like "())" or "((()". false if str is null, or if str has any character other than right or left parentheses, or if the right and left parentheses do not match. System.out.println( matchingParen( ) ); System.out.println( matchingParen( "(())" ) ); System. out.println( matchingParen( "(()))" ) ); System.out.println( matchingParen( "((x))" ) ); System.out.println( matchingParen( "()))") ); System.out.println( matchingParen( null ) ); //true //true //true //false //false //false Hint: You may check the first and last chars, and then recur on what's inside them. You may also find it easier to use a helper method.

Is there a way to create a java program on Branching and selecting method on problems like this? Suppose that we are working for an online service that provides a bulletin board for its users. We would like to give our users the option of filtering out profanity. Suppose that we consider the words cat dog and rabbit to be profane. Write a program that reads a string from the keyboard and test whether the string contain any one of these words. Your program should find words like cAt that differ only in case. Have your program reject only lines that contain one or more of the three words exactly. For example, concatenation is a small category should not be considered profane. This problem can be solved easily. If you add a space to the beginning of the string and a space at the end of the string you only need to check if space cat space or space dog space or space rabbit space is in the string. Use three if statements; one for each word. If one or more of the words are there set...

Show a definition for a recursive Java method long powerOf2(int n) that returns the value of 2" (assume n is non-negative).

Write a recursive function in Java that accepts an integer as input and returns 1 + 1/2 + 3 + 1/4 + ...(n or 1/n). The answer is the sum of the odd integers from 1 to n plus the sum of the reciprocals of the even integers.

Design and implement a program that implements Euclid’s algorithm for finding the greatest common divisor of two positive integers. The greatest common divisor is the largest integer that divides both values without producing a remainder. In a class called DivisorCalc, define a static method called gcd that accepts two integers, num1 and num2. Create a driver to test your implementation. The recursive algorithm is defined as follows:gcd (num1, num2) is num2 if num2 <= num1 and num2evenly divides num1gcd (num1, num2) is gcd(num2, num1) if num1 < num2gcd (num1, num2) is gcd(num2, num1%num2) otherwise

Use java and correctly indent code.