solving linear programming problems by the graphical method is limited

Write a LISP function that returns the smaller of two numbers. If x is less than or equal to y, return x. If y is less than or equal to x, return y.

Provide an illustration of how the Structured Programming Theorem may be used to get rid of GOTO uncertainty and make spaghetti code easier to understand. In the essay of the required length that you are going to write, you should only use your own words.

In C++, please and thank you.

Find the big-oh runtime for the c++ function given

How to decide when to use dynamic programming or recursion when solving a problem in Python?

Finding the longest common substring in two strings is a problem that lends itself to a dynamic programming solution. For example, the longest common substring in the terms "raven" and "havoc" is "av". Create a whole programme in C# for it.

import numpy as npfrom scipy.optimize import minimizeimport matplotlib.pyplot as pltimport pickle #Implement the function calAnaliticalSolution def calAnaliticalSolution(X,y): # Inputs: # X = N x d # y = N x 1 # Output: # w = d x 1 (which is the parameter calculated from data X and label y using alalytical solution)​ # IMPLEMENT THIS METHOD - REMOVE THE NEXT LINE w = np.zeros((X.shape[0],1))​ return w #Implement the function calRegressionError def calRegressionError(w,Xtest,ytest): # Inputs: # w = d x 1 # Xtest = N x d # ytest = N x 1 # Output: # mse = scalar value (which is the error of the regression model)​ # IMPLEMENT THIS METHOD - REMOVE THE NEXT LINE mse = 0​ return mse Xtrain,ytrain,Xtest,ytest = pickle.load(open('diabetes.pickle','rb')) ​x1 = np.ones((len(Xtrain),1))x2 = np.ones((len(Xtest),1))​Xtrain_i =...

How to draw a moving car in c+ + computer graphics

Problem 4 We can use lists of numbers like l to represent a mathematical vector. Recall from math classes that a vector is an object with a magnitude and direction. The magnitude is the sqrt of the sum of the squares (for a vector (x,y) it's the Pythagorean theorem for the magnitude (x^2 + y^2)**(1/2)). For a vector of any other length, the formula generalizes to (l[0]^2 + l[1]^2 + l[2]^2 + ... )**(1/2). For this problem use l from Problem 1 and a for loop to compute the magnitude of l with the result stored in l_mag. For l above, its magnitude is 12.96. Python gives you the ** exponentiation operator to raise a number to a power. You could also import math and use math.sqrt(). l = [1, 2, 3, 4, 5, 7, 8] Please give proper explanation and typed answer only.