solve in C please. Implement the following two functions that get a string, and compute an array of non-empty tokens of the string containing only lower-case letters. For example: ●くろまる For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"]. ●くろまる For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"]. ●くろまる For a string "abc 12EFG

solve in C please.

Implement the following two functions that get a string, and compute an array of non-empty
tokens of the string containing only lower-case letters. For example:
●くろまる For a string "abc EFaG hi", the list of tokens with only lower-case letters is ["abc", "hi"].
●くろまる For a string "ab 12 ef hi ", the list of such tokens is ["ab","ef","hi"].
●くろまる For a string "abc 12EFG hi ", the list of such tokens is ["abc","hi"].
●くろまる For a string " abc ", the list of such tokens is ["abc"].
●くろまる For a string "+*abc!! B" the list of such tokens is empty.
That is, we break the string using the spaces as delimiters (ascii value 32), and look only at the
tokens with lower-case letters only .
1. The function count_tokens gets a string str, and returns the number of
such tokens.
int count_tokens(const char* str);
For example
●くろまる count_tokens("abc EFaG hi") needs to return 2.
●くろまる count_tokens("ab 12 ef hi") needs to return 3.
●くろまる count_tokens("ab12ef+") needs to return 0.
2. The function get_tokens gets a string str, and returns the array with the
tokens containing only lower-case letters in the correct order. The length of the array
should be the number of tokens, computed in count_tokens.
char** get_tokens(const char* str);
For example:
●くろまる get_tokens("abc EFaG hi") needs to return ["abc","hi"]
●くろまる get_tokens("++a+ b + c") needs to return ["b","c"].
●くろまる get_tokens("ab12ef+") needs to return either NULL or an empty array.