PYTHON! Can someone help me with this? I want an iterative solution. Not a recursive solution Write an iterative function that takes an array of strings as its argument and returns an array of ints that is the length of each corresponding string. In other words, [‘foo’, ‘bar’, ‘class’] -> [3,3,5]

Your Friendly Array Neighbor Program only in java not in python Create a Java program that takes an array called ar as an input that keeps track of arrays. Every day a new array is produced using the array of the previous day. On the n’th day, the following operations are performed on the array of day n – 1 to produce the array of day n: -If an element is smaller than both left and right neighbor, then this element is incremented -If an element is bigger than both its left neighbor and its right neighbor, then this element is decremented. -The first and last elements should never change Eventually after some days the array will not change, some examples: Example: Input from user: ar = [6,2,3,4] Output from program: [6,3,3,4] After the first day the array is changed from [6,2,3,4] to [6,3,3,4] and no further operations may be completed. Example: Input from user: ar = [1,6,3,4,3,5] Output from program: [1,4,4,4,4,5] After the first day the array is changed from [1,6,3,4,3,5]...

PLease! in c++ Write a function named "getNonNegativeSum" that takes in 4 input parameters: -a pointer to thearray of integers-its size, -the index tostart the sum from -the count of how many numbers from that starting index It will return the sum of all values from the startingindex with the number count of how many. It will add to the sum if the number in the array is positiveand skip all negative values. If there is an error in the indexor not enough numbers to count, it will return -1. For example,int numList[] = {10, 20, -1, 30}; If the starting index is 1 and the count of 3, it will return 50 If the starting index is 2 and the count of 2, it will return 30 If the starting index is -1 and the count of 2, it will return -1 If the starting index is 2and the count of 5, it will return -1.int priceList[] = {10, 20, 30, -1, 40}; If the starting index is 0, and the count is 1, it will return 10 If the starting index is 1, and the count is 3, itwill return 50 If the starting index is 0,...

Question: First write a function mulByDigit :: Int -> BigInt -> BigInt which takes an integer digit and a big integer, and returns the big integer list which is the result of multiplying the big integer with the digit. You should get the following behavior: ghci> mulByDigit 9 [9,9,9,9] [8,9,9,9,1] Your implementation should not be recursive. Now, using mulByDigit, fill in the implementation of bigMul :: BigInt -> BigInt -> BigInt Again, you have to fill in implementations for f , base , args only. Once you are done, you should get the following behavior at the prompt: ghci> bigMul [9,9,9,9] [9,9,9,9] [9,9,9,8,0,0,0,1] ghci> bigMul [9,9,9,9,9] [9,9,9,9,9] [9,9,9,9,8,0,0,0,0,1] ghci> bigMul [4,3,7,2] [1,6,3,2,9] [7,1,3,9,0,3,8,8] ghci> bigMul [9,9,9,9] [0] [] Your implementation should not be recursive. Code: import Prelude hiding (replicate, sum)import Data.List (foldl') foldLeft :: (a -> b -> a) -> a -> [b] -> afoldLeft =...

1. The sorted values array contains 16 integers 5, 7, 10, 13, 13, 20, 21, 25, 30,32, 40, 45, 50, 52, 57, 60. Indicate the sequence of recursive calls that are made tobinaraySearch, given an initial invocation of binarySearch(32, 0, 15).show only the recursive calls. For example, initial invocation is binarySearch(45,0,15)where the target is 45, first is 0 and last is 15.

Given a file of unsorted words with mixed case: read the entries in the file and sort those words lexicographically. The program (in c++) should then prompt the user for an index, and display the word at that index. Since you must store the entire list in an array, you will need to know the length. The "List of 1000 Mixed Case Words" contains 1000 words. You are guaranteed that the words in the array are unique, so you don't have to worry about the order of, say, "bat" and "Bat."

Write a C++ Program that does the following: Implement a sort function using a vector.Ask the user to enter numbers to be sorted. Add them to the vector. The user will signal the end of input bygiving you a negative number.Then, sort the vector. Because this is a vector, you don’t need to pass the number of entriesin the vector.Then, print out the vector in order.Remember the following things about vectors.a) You declare a vector v of ints by saying vector⟨int⟩ v;b) You add elements to a vector by saying v.push back(thing to be added);c) You access elements of a vector with [ ] just like an array;d) One of the vector member functions is .length()

Give me correct code. Downvote for incorrect and copied code. Changes in function..

Write a function that verifies if a given number exists in an array of floats. The function is supposed to return the first position in where the number is encountered. If the given number does not exist, the function returns –1. Then write a complete program that asks the user to enter an array of 8 floats and calls the function. The prototype of the function should be like: int Search (floats a[ ], int n, float number); Example: Consider the following array of floats int x[8]={2.1, 5.0, 9.8, 4.4, 6.8, 12.88, 9.87, 4.56}; If the number to be searched is 5.4, the function returns –1 If the number to be searched is 9.8,the function returns 2 C++ language only.