please code in python 1). Multiplication using Addition Write a function: mul(a,b) that will compute and return the product of two positive integers a and b using only a for loop and the addition operator ( + ). Then, write a new function mul2(a,b) that does the same thing, but uses a while loop rather than a for loop. 2). Exponentiation using Multiplication Write a function expo(x,y) that computes and returns the exponent xy using only a loop and the multiplication operator. Then, adjust it so that rather than using the multiplication operator, it uses one of the multiplication functions you wrote in part 1. Hints: xy is equal to (x * x * x * x ... x), y times. When you’re computing a sum using a loop, you start at 0, since anything + 0 is itself. When you’re computing a product using a loop, you start at ?, since anything * ? is itself (fill in the ?). If you wrote your mul function from part 1 correctly, then the following two lines should have the same effect, so you can use one to replace the other. var = foo * bar var = mul(foo, bar)

please code in python

1). Multiplication using Addition

Write a function: mul(a,b) that will compute and return the product of two positive integers a and b using only a for loop and the addition operator ( + ).

Then, write a new function mul2(a,b) that does the same thing, but uses a while loop rather than a for loop.

2). Exponentiation using Multiplication

Write a function expo(x,y) that computes and returns the exponent x^y using only a loop and the multiplication operator.

Then, adjust it so that rather than using the multiplication operator, it uses one of the multiplication functions you wrote in part 1.

Hints:

• x^y is equal to (x * x * x * x ... x), y times.
• When you’re computing a sum using a loop, you start at 0, since anything + 0 is itself. When you’re computing a product using a loop, you start at ?, since anything * ? is itself (fill in the ?).
• If you wrote your mul function from part 1 correctly, then the following two lines should have the same effect, so you can use one to replace the other.
  • var = foo * bar
  • var = mul(foo, bar)