Part 2 - OddOrEven Class Write a program that prompts the user to enter an integer. The program should display "The input is odd" to the screen if the input is odd and displays "The input is even" to the screen if the input is even. Hint: Consider using the mod (%) operator

2. A password is called STRONG if it holds all of the following properties: (a) It has at least 8 characters (b) It contains at least one lower case letter, and at least one upper case letter (c) It does not contain any blank space Write down a program that will take a password as input to a string and will print a message indicating whether it is STRONG or WEAK. Sample input: Strange Sample output: The password is WEAK solve in C program language

Summary Interest on a credit card's unpaid balance is calculated using the average daily balance. Suppose that netBalance is the balance shown in the bill, payment is the payment made, d1 is the number of days in the billing cycle, and d2 is the number of days payment is made before billing cycle. Then, the average daily balance is: averageDailyBalance = (netBalance * d1 payme If the interest rate per month is, say, 0.0152, then the interest on the unpaid balance is: interest averageDailyBalance * 0.0152 Instructions Write a program that accepts as input netBalance, d1, payment, d2, and interest rate per month ( interestRate).

Rock, Paper, Scissors Game - MUST BE WRITTEN IN PSEUDOCODE

Analyze the following code: int x = 0;int y = ((x < 100) && (x > 0)) ? 1: -1; The code has syntax error. y becomes 1 after the code is executed. y becomes -1 after the code is executed. The code has run time error.

mystery_value = 5 #You may modify the lines of code above, but don't move them!#When you Submit your code, we'll change these lines to#assign different values to the variables. #Write a program that divides mystery_value by mystery_value#and prints the result. If that operation results in an#error, divide mystery_value by (mystery_value + 5) and then#print the result. If that still fails, multiply mystery_value#by 5 and print the result. You may assume one of those three#things will work.##You may not use any conditionals.# #Add your code here!

C Language - Write a program that takes in three integers and outputs the largest value. If the input integers are the same, output the integers' value.

Convert totalMeters to hectometers, decameters, and meters, finding the maximum number of hectometers, then decameters, then meters. Ex: If the input is 815, then the output is: Hectometers: 8 Decameters: 1 Meters: 5 Note: A hectometer is 100 meters. A decameter is 10 meters. 1 #include 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 15 16 17 18 int totalMeters; int numHectometers; int numDecameters; int numMeters; cin>>totalMeters; cout << "Hectometers: cout << "Decameters: cout << "Meters: " << numMeters << endl; " << numHectometers << endl; << numDecameters << endl; 2 3

Financial Application:• Write a program that computes future investment value at a given interest rate for aspecified number of months and prints the report shown in the sample output. • Given the annual interest rate, the interest amount earned each month is computedusing the formula: Interest earned = investment amount * annual interest rate /1200 (=months * 100) • Write a method, computeFutureValue, which receives the investment amount, annualinterest rate and number of months as parameters and does the following: o Prints the interest amount earned each month and the new value of theinvestment (hint: use a loop). o Returns the total interest amount earned after the number of months specified bythe user. The main method will:o Ask the user for all input needed to call the computeFutureValue method.o Call computeFutureValueo Print the total interest amount earned by the investment at the end of thenumber of months entered by the user. Sample Program runningEnter the investment...

9: perfect.cpp) A number is called perfect if the sum of its divisors is equal to the original number. A number is called deficient if the sum of its divisors is less than the original number. A number is called abundant if the sum of its divisors is more than the original number. Write a program that answers the following questions: What numbers below 5000 are perfect? What odd numbers below 5000 are abundant? What are the relative proportions of deficient, abundant, and perfect numbers? 5000 should be in a global constant.

T/F The body of a method may be empty

Assign Barbecue's data member numberOfCalories with a value read from input. Then, assign Ham and Cheese's data member numberOfCalories with another value read from input. Input will contain two integer numbers. Only the *your code goes here can be affected, the rest of the program cannot be changed. Program below: ----------------------------#include <iostream>#include <vector>#include <string>using namespace std; struct PizzaInfo {string pizzaName;int numberOfCalories;}; int main() {vector<PizzaInfo> availablePizzas(2); availablePizzas.at(0).pizzaName = "Barbecue";availablePizzas.at(1).pizzaName = "Ham and Cheese"; /* Your code goes here */ cout << "A " << availablePizzas.at(0).pizzaName << " slice contains " << availablePizzas.at(0).numberOfCalories << " calories." << endl;cout << "A " << availablePizzas.at(1).pizzaName << " slice contains " << availablePizzas.at(1).numberOfCalories << "...

#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to...