C++ for Engineers and Scientists
C++ for Engineers and Scientists
4th Edition
ISBN: 9781133187844
Author: Bronson, Gary J.
Publisher: Course Technology Ptr
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Please answer the exercise below(C programme)

[画像:Mark 10 The program below uses pointer arithmetic to determine the size of a 'char' variable. By using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the pointer point to the next element of the same type. For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only because each char is 1 byte. 1. 2. Compile and run the program and see what it does. (2 Marks) Write some code that does pointer arithmetic with a pointer to an int and determine how big an int is before and after adding a 1. (4 Marks) 3. Same idea figure out how big a double is, by using pointer arithmetic and printing out the value of the pointer before and after adding a 1. (4 Marks) #include <stdio.h> int main() { char c='2'; char *cp = &c; printf("cp is 0x%08x\n", cp); printf("The character at cp is %c\n", *cp); /* Pointer arithmetic see what cp+1 is */ cp = cp+1; printf("cp is 0x%08x\n", cp); /* Do not print *cp, because it points to memory not allocated to your program */ return 0; }]
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Transcribed Image Text:Mark 10 The program below uses pointer arithmetic to determine the size of a 'char' variable. By using pointer arithmetic we can find out the value of 'cp' and the value of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic: adding one to a pointer makes the pointer point to the next element of the same type. For a pointer to a char, adding 1 really just means adding 1 to the address, but this is only because each char is 1 byte. 1. 2. Compile and run the program and see what it does. (2 Marks) Write some code that does pointer arithmetic with a pointer to an int and determine how big an int is before and after adding a 1. (4 Marks) 3. Same idea figure out how big a double is, by using pointer arithmetic and printing out the value of the pointer before and after adding a 1. (4 Marks) #include <stdio.h> int main() { char c='2'; char *cp = &c; printf("cp is 0x%08x\n", cp); printf("The character at cp is %c\n", *cp); /* Pointer arithmetic see what cp+1 is */ cp = cp+1; printf("cp is 0x%08x\n", cp); /* Do not print *cp, because it points to memory not allocated to your program */ return 0; }
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