java Suppose queue is defined as LinkedQueue queue = new LinkedQueue<>(); Show what is written by the following segment of code. SHOW YOUR WORK.

Add the three classic operations of Queues in the MagazineList.java to make it become a queue. Add testing code in MagazineRack.java to test your code. (You do not need to modify Magazine.java) Magazine.java : public class Magazine {private String title;//-----------------------------------------------------------------// Sets up the new magazine with its title.//-----------------------------------------------------------------public Magazine(String newTitle){ title = newTitle;}//-----------------------------------------------------------------// Returns this magazine as a string.//-----------------------------------------------------------------public String toString(){return title;}} MagazineList.java : attached the image below MagazineRack.java: public class MagazineRack{//----------------------------------------------------------------// Creates a MagazineList object, adds several magazines to the// list, then prints...

JAVA please Given main() in the ShoppingList class, define an insertAtEnd() method in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts where 4 is the number of items to be inserted; Kale, Lettuce, Carrots, Peanuts are the names of the items to be added at the end of the list. The output is: Kale Lettuce Carrots Peanuts Code provided in the assignment ItemNode.java:

b. Write out the order of elements that are contained in a queue after the following operations are performed. myQueue.enqueue(new Integer(16)); myQueue.enqueue(new Integer(12)); Integer num1 = myQueue.dequeue(); myQueue.enqueue(new Integer(6)); myQueue.enqueue(new Integer(8)); myQueue.enqueue(new Integer(30)); myQueue.enqueue(new Integer(24)); myQueue.enqueue(new Integer(18)); myQueue.dequeue(); myQueue.dequeue(); myQueue.dequeue(); myQueue.enqueue(new Integer(38); Show how step by step process of arriving at your answer.

Implement a circular queue by writing circular.h and circular.c. Here are the contents of circular.h: #define QUEUE_SIZE 100 typedef struct { int head; int tail; int itemCount; int items[QUEUE_SIZE]; } CircularQueue; void CircularInitialize(CircularQueue * q); void CircularEnqueue (CircularQueue * q, int value); int Circular Dequeue (CircularQueue * q, int *pValue); Using an array, implement a circular queue of up to 100 elements of type integer. Implement the functions CircularEnqueue() and Circular Dequeue () to place numbers in the head of the queue and read them from the tail of the queue tail. A circular queue only saves the last n entries (where n is the number of elements in the queue). Overwrite the oldest entries with newest entries once the queue is full.

15. If a queue is implemented under an ArrayList, how much time does a queue add an item? a. 0(1) b. O(n) с. О(n2) d. 0(log n)

def has_at_least(queue: Queue, n: int) -> bool:"""Return true iff queue contains at least n items. Precondition: n >= 0 >>> queue = Queue()>>> queue.enqueue(1)>>> queue.enqueue(2)>>> queue.enqueue(3)>>> has_at_least(queue, 3)True"""

Java: Which of the following operations has the least running time in a Queue (assume that only Queue interface operations are available; some operations may require use of an additional temporary queue)? Multiple choice. Deleting the element at the rear of the queue Checking if an element x is present in the queue Finding the number of elements in the queue all of the above have identical worst case running time

import java.util.*;import java.io.*; public class HuffmanCode { private Queue<HuffmanNode> queue; private HuffmanNode overallRoot; public HuffmanCode(int[] frequencies) { queue = new PriorityQueue<HuffmanNode>(); for (int i = 0; i < frequencies.length; i++) { if (frequencies[i] > 0) { HuffmanNode node = new HuffmanNode(frequencies[i]); node.ascii = i; queue.add(node); } } overallRoot = buildTree(); } public HuffmanCode(Scanner input) { overallRoot = new HuffmanNode(-1); while (input.hasNext()) { int asciiValue = Integer.parseInt(input.nextLine()); String code = input.nextLine(); overallRoot =...