Java programming- Prompt the user to enter an integer n, write a program to take input value of n and print the product of first n natural numbers. Given: 0

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Use cin to read integers from input until 1000 is read. For each remaining integer read before 1000, if the integer is positive, output the integer followed by a newline and add the integer to totalOfSelected. Ex: If the input is 8 24 15 -6 14 1000, then the output is: 8 24 15 14 The sum of all positive values is 61 #include <iostream> using namespace std; int main() { int inputValue; int totalOfSelected; /* Your code goes here */ cout << "The sum of all positive values is " << totalOfSelected << endl; return 0; }

Problem #3: Write code that divides a positive number n in half until the resulting number is less than 1. For this exercise, use a method that doesn't require you to convert the integer n to a different data type. For example, if n = 5, the first time through the loop should result in 2.5, the second time through should result in 1.25, and the third time through should result in 0.625. The loop should not be executed a forth time since 0.625 =10: 5 4 3 print (n) HN W 2 (missing line) n=n//10 1 print (r)

Use cin to read integers from input until 100 is read. For each remaining integer read before 100, if the integer is negative, output the integer followed by a newline and add the integer to sumOfNegative. Ex: If the input is 11 -14 -11 -4 100, then the output is: -14 -11 -4 The sum of all negative values is -29 #include <iostream> using namespace std; int main() { int inputNumber; int sumOfNegative; /* Your code goes here */ cout << "The sum of all negative values is " << sumOfNegative << endl; return 0; }

Modify the given R programming code to print numbers only upto 5.