java Given Array : ARRAY[] = [11, 21, 33, 40, 50] Write a full and complete recursive implementation of the Binary Search Algorithm such that you find your target element 21 in O(log2(n)) time complexity overall and O(1) space complexity. Here, n is the length of the list of input integers (array). We will not be considering any memory used by recursion.

Write a java class named First_Last_Recursive_Merge_Sort that implements the recursive algorithm for Merge Sort. You can use the structure below for your implementation. public class First_Last_Recursive_Merge_Sort { //This can be used to test your implementation. public static void main(String[] args) { final String[] items = {"Zeke", "Bob", "Ali", "John", "Jody", "Jamie", "Bill", "Rob", "Zeke", "Clayton"}; display(items, items.length - 1); mergeSort(items, 0, items.length - 1); display(items, items.length - 1); } private static <T extends Comparable<? super T>> void mergeSort(T[] a, int first, int last) { //<Your implementation of the recursive algorithm for Merge Sort should go here> } // end mergeSort private static <T extends Comparable<? super T>> void merge(T[] a, T[] tempArray, int first, int mid, int last) { //<Your implementation of the merge algorithm should go here> } // end merge //Just a quick method to display the whole array. public...

convert the recursion code to alterative code in java public int array11(int[] nums, int index) { if (index == nums.length) return 0; if (nums[index] == 11) return 1 + array11(nums, index + 1); return array11(nums, index + 1); }

Java programming homework please help

Write a program to implement insertion sort and also test this using an unsorted array in java

Java Quick Sort but make it read the data 10, 7, 8, 9, 1, 5 from a file not an array // Java implementation of QuickSort import java.io.*; class GFG { // A utility function to swap two elements static void swap(int[] arr, int i, int j) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } /* This function takes last element as pivot, places the pivot element at its correct position in sorted array, and places all smaller (smaller than pivot) to left of pivot and all greater elements to right of pivot */ static int partition(int[] arr, int low, int high) { // pivot int pivot = arr[high]; // Index of smaller element and // indicates the right position // of pivot found so far int i = (low - 1); for (int j = low; j <= high - 1; j++) { // If current element is smaller // than the pivot if...