In C language, implement the function that gets a string str, changes all digits of str to 0 (zero), and returns the number of digits in the string. int digits_to_zero (char* str); For example: If str is "12ab0", then the function should change it to "00ab0", and return 3. If str is "abcde", then the function should keep it as is, and return 0. [Hint 1: you can check if a char is a digit using its numerical value. The numerical values of the digits are consecutive. For example, we have '3' + 2 =='5'] [Hint 2: you can also use the function isdigit (char c) implemented in the library https://www.programiz.com/c-programming/library-function/ctype.h/isdigit]

In C++ Write a program with a function that implements the Addition Algorithm with base 10 addition and accept two positive integer string value and perform addition operation and outputs the result.

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in C++ solve the following question in the picture :

Write a function that converts a floating-point number to a string. Provide a parameter variable for the number of digits after the decimal point. util.cpp 3 1 #include #include #include #include 6 using namespace std; 7 8 string double_to_string(double x, int digits) 9 { 10 11 } CodeCheck Reset

Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'

Write a complete function called Main() that asks the user for an input string, then creates and prints a report of how many of each character occurred in that string. For example, here is a sample run: >>> Main() Enter a string --- computer science rocks! 2 ! 1 c 4 e 3 i 1 >>> If you can put it in alphabetical order too that would be great!

Using Python write a string-comparison function named strNcompare that compares up to n characters of a string s1 with the other string s2. The function must return 0, -1, or 1 if the first n-character portion of s1 is equal to, less than, or greater than the corresponding first n-character portion of s2, respectively. (1) You must use the following function definition: def strNcompare(s1, s2, n): (2) String comparison must be case-insensitive. For example, the strNcompare function must return 0 for the s1 value of ‘tommy’ and the s2 value of ‘TOMMY’. (3) You should not use a loop such as the while loop and the for loop inside the strNcompare function. Then write a Python program that receives two words and the number of characters for comparison, calls the strNcompare function, and then shows the result. Your program keeps doing this until the user enters the value of -1. Your program displays the message ‘String comparison [1(play), -1(quit)]: ’ and receives the value 1 or -1...

Write a C++ program that takes a 4-digit number from user as and input and displays all the combinations of those digits.For Example: Enter number: 5321Possible Combinations are:5321, 5312, 5231, 5213, 5123, 5132 3521, 3512, 3251, 3215, 3125, 31521523, 1532, 1253, 1235, 1325, 1352 2513, 2531, 2153, 2135, 2315, 2351